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\(\frac{3-x}{5-x}=\frac{9}{25}\)
\(\Rightarrow\left(3-x\right)\cdot25=\left(5-x\right)\cdot9\)
\(75-25x=45-9x\)
\(75-25x+9x=45\)
\(14x=30\)
\(x=30\div14\)
\(x=\frac{15}{7}\)

a) \(x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{2}{25}\)
b) \(x=\frac{5}{11}+\frac{4}{-9}=\frac{45}{99}+\frac{-44}{99}=\frac{1}{99}\)
c) \(\frac{5}{9}+\frac{x}{-1}=\frac{-1}{3}\)
\(\Rightarrow\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}\)
\(\Rightarrow\frac{x}{-1}=\frac{-8}{9}\)
\(\Rightarrow x=\frac{\left(-8\right).\left(-1\right)}{9}=\frac{8}{9}\)

\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(\Leftrightarrow\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)
\(\Leftrightarrow\left(2x+\frac{3}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x+\frac{3}{5}=\frac{3}{5}\\2x+\frac{3}{5}=-\frac{3}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\2x=-\frac{6}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{3}{5}\end{cases}}\)
_Tần vũ_
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(\Leftrightarrow3\left(3x-\frac{1}{2}\right)^3=-\frac{1}{9}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=-\frac{1}{27}\)
\(\Leftrightarrow\left(3x-\frac{1}{2}\right)^3=\left(-\frac{1}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(\Leftrightarrow3x=\frac{1}{6}\)
\(\Leftrightarrow x=\frac{1}{18}\)
_Tần Vũ_

1. \(x=\frac{61}{42}\)
2. \(x=\frac{-36}{5}\)
3. \(x=\frac{13}{11}\)
4. \(x=\frac{1}{12}\)
5.\(x=\frac{-5}{2}\)

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\\ \left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\\ \left(x+\frac{1}{5}\right)^2=\frac{9}{25}\\ \left|\left(x+\frac{1}{5}\right)\right|=\frac{3}{5}\)
TH1: \(x=\frac{3}{5}-\frac{1}{5}\\ x=\frac{2}{5}\)
TH2: \(\left|\left(x+\frac{1}{5}\right)\right|=-\frac{3}{5}\\ x=-\frac{3}{5}-\frac{1}{5}\\ x=-\frac{4}{5}\)
\(a,\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{2}{5}\)
\(b,-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Rightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}+\frac{24}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Rightarrow3x-\frac{7}{9}=-\frac{2}{3}\)
\(\Rightarrow3x=-\frac{2}{3}+\frac{7}{9}\)
\(\Rightarrow3x=\frac{1}{9}\)
\(\Rightarrow x=\frac{1}{27}\)
\(c,\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\)

1/2 * x - 3/5 = -4 /5
1/2 * x = - 4 /5 + 3/5
1/2* x = -1/5
x = -1/5 : 1/2
x = -1/5 *2
x = -2 /5
Vay x = -2/5
b ) ( x - 2/3 ) : -3 /7 = - 9/14
x - 2/3 = - 9/14 * -3/7
x - 2/3 = 27/98
x = 27/98+ 2/3
x = 81/294 + 196/ 294
x = 277/294
Vay x= 277/294
Ban oi , k cho mk nha .
\(x^2-25\%x=0\)
\(x.x-\frac{1}{4}x=0\)
\(x.\left(x-\frac{1}{4}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-\frac{1}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=0+\frac{1}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=\frac{1}{4}\end{cases}}}\)
~ Hok tốt ~
\(\frac{3-x}{5}=\frac{9}{25}\)
\(\Rightarrow\left(3-x\right).25=9.5\)
\(75-25x=45\)
\(25x=75-45\)
\(25x=30\)
\(x=\frac{30}{25}\)
\(x=\frac{6}{5}\)
1,2