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a) 15 - (25 - x) = 2x - 17
15 - 25 + x = 2x - 17
x - 2x = -17 - 15 + 25
-x = -7
x = 7
b) 42 - (12 - x) = 2x - 15
42 - 12 + x = 2x - 15
x - 2x = -15 - 42 + 12
-x = -45
x = 45
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a) Mình chưa thấy x ở đâu nha bạn
b) Ta có : ( 2.x - 15) 5 = ( 2.x - 15 )3
<=. ( 2.x - 15 )5 - ( 2.x - 15 )3 = 0
<=> ( 2.x -15 )3 . [ ( 2.x - 15 )2 - 1 ] = 0
<=> \(\orbr{\begin{cases}\left(2.x-15\right)^3=0\\\left[\left(2.x-15\right)^2-1\right]=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2.x-15=0\\2.x-15=1\end{cases}\Leftrightarrow}\orbr{\begin{cases}2.x=15\\2.x=16\end{cases}\Leftrightarrow}\orbr{\begin{cases}\frac{15}{2}\left(L\right)\\x=8\end{cases}}}\)
Vậy x = 8
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các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
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x=5
-2x+15=(-2) . 5+15=-10+15=5
3x-7=3.5-7=15-7=8
19-x=19-5=14
5<8<14
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1/7x-x=521:519+3.22-70
6x=52+3.4-1
6x=25+12-1
6x=25+11
6x=36
x=36:6
x=3
2/7x-2x=617:615+44:11
5x=62+4
5x=36+4
5x=40
x=40:5
x=8
3/6x+x=511:59+3
7x=52+3
7x=25+3
7x=28
x=28:7
x=4
a) 7x - x = 521: 519 + 3.22 - 70
6x = 52 + 3. 4 - 1
6x = 25 + 12 - 1
6x = 37 - 1
6x = 36
x = 36 : 6
x = 6
b) 7x - 2x = 617 : 615 + 44:11
5x = 62 + 4
5x = 36 +4
5x = 40
x = 40 :5
x = 8
c) 6x + x = 511 : 59 + 3
7x = 52 +3
7x = 25 +3
7x = 28
x = 28 : 7
x = 4
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a/(x-5)^4=9x-5)^6\(\Rightarrow\) TH1:x-5=1\(\rightarrow\) x=6
\(\Rightarrow\) TH2:x-5=-1\(\rightarrow\) x=4
\(\Rightarrow\) TH3:x-5=0\(\rightarrow\) x=5
vậy....................
b/(2x-15)^5=(2x-15)^6\(\Rightarrow\) 2x-15=1\(\rightarrow\) 2x=16\(\rightarrow\)x=8
\(\Rightarrow\) 2x-15=0\(\rightarrow\)2x=15\(\rightarrow\)x=7.5
vậy................
a) Có : ( x-5 ) \(^4\) = ( x - 5 ) \(^6\)
\(\Rightarrow\left(x-5\right)^6:\left(x-5\right)^4=1\Rightarrow\left(x-5\right)^2=1\)
\(\Rightarrow x-5=1\) hoặc \(x-5=-1\)
\(\Rightarrow x=1+5\) hoặc \(x=-1+5\)
\(\Rightarrow x=6\) hoặc \(x=4\)
b) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\left(2x-15\right)^5:\left(2x-15\right)^3=1\Rightarrow\left(2x-15\right)^2=1\)
\(\Rightarrow2x-15=1\) hoặc \(2x-15=-1\)
\(\Rightarrow2x=16\) hoặc \(2x=14\)
\(\Rightarrow x=8\) hoặc \(x=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow2x-15=\orbr{\begin{cases}0\\1\end{cases}}\)vì chỉ có \(0^5=0^3;1^5=1^3\)
\(\Rightarrow2x=\orbr{\begin{cases}15\\16\end{cases}}\)
\(\Rightarrow x=\orbr{\begin{cases}\frac{15}{2}\\8\end{cases}}\)
=> x-6-2x = 15
=> -x = 15+6 = 21
=> x = -21
=> 15-x-5+2x = 19
=> x = 9
Tìm x ak bạn