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Bài làm :
\(\frac{9}{10}\times y=\frac{2}{3}\)
\(y=\frac{2}{3}:\frac{9}{10}\)
\(y=\frac{20}{27}\)
Vậy \(x=\frac{20}{27}\) .
Học tốt nhé
\(\frac{9}{10}\times y=\frac{2}{3}\)
\(y=\frac{2}{3}\div\frac{9}{10}\)
\(y=\frac{20}{27}.\)
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Ta có:\(\frac{10}{13}<\frac{12}{x}<\frac{10}{12}\)
=>\(\frac{120}{156}<\frac{120}{10x}<\frac{120}{144}\)
=>156>10x>144
=>\(\frac{156}{10}>x>\frac{144}{10}\)
=>15 lớn hơn hoặc bằng x lớn hơn hoặc bằng 14
=>x\(\in\){15,14}
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\(\frac{125}{61}-\frac{22}{39}+\frac{100}{39}-\frac{3}{61}=\left(\frac{125}{61}-\frac{3}{61}\right)+\left(\frac{100}{39}-\frac{22}{39}\right)\)
\(=\frac{122}{61}+\frac{78}{39}=2+2=4\)
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\(\frac{82}{59}+\frac{95}{91}+\frac{36}{59}+\frac{87}{91}=\left(\frac{82}{59}+\frac{36}{59}\right)+\left(\frac{95}{91}+\frac{87}{91}\right)\)
\(=\frac{118}{59}+\frac{182}{91}=2+2=4\)
\(\frac{82}{59}+\frac{95}{91}+\frac{36}{59}+\frac{87}{91}\) \(=\left(\frac{82}{59}+\frac{36}{59}\right)+\left(\frac{95}{91}+\frac{87}{91}\right)=\frac{118}{59}+\frac{182}{92}=2+2=4\)
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5 chục + 6 đơn vị