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\(16^4:4^2\)
\(=\left(4^2\right)^4:4^2\)
\(=4^8:4^2=4^6\)
b) \(27^8:9^4\)
\(=\left(3^3\right)^8:\left(3^2\right)^4\)
\(=3^{24}:3^8=3^{16}\)
Cậu còn lại bạn làm tương tư nha
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Bạn ấy lm câu a rùi mik lm 3 câu còn lại nha
\(27^{16}:9^{10}\)
\(=3^{16}\cdot9^{16}:9^{10}\)
\(=9^8\cdot9^6=9^{14}\)
\(125^3:25^4\)
\(=5^3\cdot25^3:25^4\)
\(=5\cdot25\cdot25^3:25^4\)
\(=5\cdot25^4:25^4\)
\(=5\cdot1=5\)
\(24^4:3^4-32^{12}:16^{12}\)
\(=8^4\cdot3^4:3^4-2^{12}\cdot16^{12}:16^{12}\)
\(=8^4-2^{12}\)
\(=4096-4096\)
\(=0\)
a. \(5^{10}.125^2.625^3=5^{10}.\left(5^3\right)^2.\left(5^4\right)^3=5^{10}.5^6.5^{12}=5^{10+6+12}=5^{28}\)
a: \(=5^{10}\cdot5^6\cdot5^{12}=5^{28}\)
b: \(=10^3\cdot10^8\cdot10^{15}=10^{26}\)
c: \(=2^{20}\cdot2^{20}=2^{40}\)
d: \(=2^{16}\cdot2^{16}\cdot3^8=2^{32}\cdot3^8\)
e: \(=\dfrac{3^{24}}{3^8}=3^{16}\)
f: \(=2^{12}\cdot2^{20}\cdot2^5=2^{37}\)
Lời giải:
\(2^{27}.3^{18}=(2^3)^9.(3^2)^9=8^9.9^9=(8.9)^9=72^9\)
\(25^4.2^8=25^4.(2^2)^4=25^4.4^4=(25.4)^4=100^4\)
\((-9)^4.27^2=9^4.27^2=(3^2)^4.(3^3)^2=3^8.3^6=3^{8+6}=3^{14}\)
\(-5^4:25=-5^4:(5^2)=-5^{4-2}=-5^2\)
Nữ hoàng cảm ơn nhưng vị thám tử tài ba có thể viết cách giải ra đc không ạ
a) a mũ 4 chia a = a mũ 3
b) ( 16 mũ 2 ) / ( 4 mũ 2 )
= ( 16 / 4 ) mũ 2
= 4 mũ 2
= 16
c) ( 25 mũ 2 ) / ( 5 mũ 2 )
= ( 25 / 5 ) mũ 2
= 5 mũ 2
= 25
\(a^4:a=a^3\)
\(16^2:4^2=\left(16:4\right)^2=4^2=16\)
\(25^2:5^2=\left(25:5\right)^2=5^2=25\)
a, \(3^{15}:3^5=3^{15-5}=3^{10}\)
b, \(4^6:4^6=4^{6-6}=4^0\)
c, \(9^8:3^2=9^8:9=9^{8-1}=9^7\)
Bài 1.
a) \(\dfrac{3}{14}.\dfrac{7}{20}+\dfrac{13}{20}=\dfrac{3}{40}+\dfrac{13}{20}=\dfrac{3}{40}+\dfrac{26}{40}=\dfrac{29}{40}\).
b) \(\left(2.3^{2010}+12.3^{2010}-3.3^{2010}\right):3^{2012}\)
\(=3^{2010}\left(2+12-3\right):3^{2012}\)
\(=3^{2010}.11:3^{2012}\)
\(=\left(3^{2010}:3^{2012}\right).11\)
\(=\dfrac{1}{9}.11\)
\(=\dfrac{11}{9}\).
Bài 2.
a) \(\left(5^{14}.25^{10}\right):125^3\)
\(=\left[5^{14}.\left(5^2\right)^{10}\right]:\left(5^3\right)^3\)
\(=\left[5^{14}.5^{20}\right]:5^9\)
\(=5^{34}:5^9\)
\(=5^{25}\).
b) \(\left(\dfrac{1}{2}\right)^5.\left(\dfrac{1}{64}\right)^9:\left(\dfrac{1}{16}\right)^5\)
\(=\dfrac{1}{2^5}.\dfrac{1}{64^9}:\dfrac{1}{16^5}\)
\(=\dfrac{1}{2^5}.\dfrac{1}{\left(2^6\right)^9}:\dfrac{1}{\left(2^4\right)^5}\)
\(=\dfrac{1}{2^5}.\dfrac{1}{2^{54}}:\dfrac{1}{2^{20}}\)
\(=\dfrac{1}{2^{59}}:\dfrac{1}{2^{20}}\)
\(=\dfrac{2^{20}}{2^{59}}\)
\(=\dfrac{1}{2^{39}}\).
\(16^6:4^2=2^{24}:2^4=2^{24-4}=2^{20}\)
\(12^n:2^{2n}=12^n:4^n=3^n\)
\(27^8:9^4=3^{24}:3^8=3^{24-8}=3^{16}\)
\(125^5:25^3=5^{15}:5^6=5^{15-6}=5^9\)
\(4^{14}.5^{28}=4^{14}.25^{14}=\left(4.25\right)^{14}=100^{14}\)
\(64^4.16^5:4^{20}=2^{24}.2^{20}:2^{40}=2^{24+20-40}=2^4=16\)
166:42 = (42)6:42 = 412:42=412-2=410
278:94=(33)8:(32)4=324:38=324-8=316
1255:253=(53)5:(52)3=515:56=515-6=59
12n:22n = (22.3)n:22n = 3n.22n:22n=3n.1 = 3n
644.165:420= (26)4.(24)5.(22)20 = 224.220:240=224+20-40 = 24