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d)
\(152-3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=-4\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=152-\left(-4\right)\)
\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=156\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=156\div3\)
\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=52\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=52-42\)
\(\Rightarrow32-2\left(36\div x^2+7\right)=10\)
\(\Rightarrow2\left(36\div x^2+7\right)=32-10\)
\(\Rightarrow2\left(36\div x^2+7\right)=22\)
\(\Rightarrow36\div x^2+7=22\div2\)
\(\Rightarrow36\div x^2+7=11\)
\(\Rightarrow36\div x^2=11-7\)
\(\Rightarrow36\div x^2=4\)
\(\Rightarrow x^2=36\div4\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x^2=3^2\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
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bn ơi
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2,Tìm số nguyên x,biết:
a,461+(x-45)=387
x-45=387-461
x-45=-74
x=-74+45
x=-29
b,6.|x-7|=18:(-3)
6.|x-7|=-6
|x-7|=-1
Vô lí vì |x-7|>0
c,7.(x-3)-5.(3-x)=11x-5
7x-21-15-5x=11x-5
7x-5x+11x=-5+21+15
-x=32
x=-32
d,4.|x-2|-18=-2
4.|x-2|=-2+18
4.|x-2|=16
|x-2|=16:4
|x-2|=4
* x-2=4 *x-2=-4
x=4+2 x=-4+2
x=6 x=-2
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3.|x+1|-2=4
3.|x+1|=4+2
3.|x+1|=6
|x+1|=6:3
|x+1|=2
Trường hợp 1 x+1=2
x=2-1
x=1
trường hợp 2
x+1=-2
x=(-2)-1
x=-3
==> x thuộc {1; -3}
k mk nha chúc học tốt
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31.(-18) + 31.(-81) - 31
= 31.(-18 - 81 - 1)
= 31.(-100) = -3100
-48 + 48.(-78) + 48.(-21) = 48.(-1 - 78 - 21) = 48. (-100) = -4800
-75.(8 - 65) - 65.(75 - 18) = -75.18 + 75.65 - 65.75 + 65.18 = 0
29.(19 - 13) - 19.(29 - 13) = 29.19 - 29.13 - 19.29 + 19.13 = 0
13.(23 + 22) - 3(17 + 28) = 13.25 - 3.45 = (10 + 3).25 - 3.45
= 10 . 25 + 3.25 - 3.45 = 10.25 - 3.(45 - 25)
= 250 - 3.20 = 250 - 60 = 190
(-25).21 . (-2)2.(|3|). (-1)2n + 2 (n \(\in\)N*)
= (-25. 4) . (21.3).1
= -100. 63 = -6300
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1) x - 2 = -6
x = -6 + 2
x = -4
2) -5 . x - ( -3 ) =13
-5 . x = 13 + ( -3 )
-5 . x = 10
x = 10 : ( -5 )
x = -2
x=3 k cho minh nhe