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Đây là cuộc thi nhé. cần sự công bằng. Mong em không tái phạm lần sau. Bạn sẽ bị khóa nick hoặc trừ 5000 điểm nhé!
BQT thân gửi em!
__BQT Lớp 6/7 Hỏi Đáp__
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Ta có: \(A=124\left(\frac{1}{1.1985}+\frac{1}{2.1986}+\frac{1}{3.1987}+...+\frac{1}{16.2000}\right)\)
\(=\frac{124}{1984}\left(\frac{1984}{1.1985}+\frac{1984}{2.1986}+\frac{1984}{3.1987}+...+\frac{1984}{16.2000}\right)\)
\(=\frac{1}{16}\left(1-\frac{1}{1985}+\frac{1}{2}-\frac{1}{1986}+\frac{1}{3}-\frac{1}{1987}+...+\frac{1}{16}-\frac{1}{2000}\right)\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{16}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+\frac{1}{1987}+...+\frac{1}{2000}\right)\right]\)
\(B=\frac{1}{1.17}+\frac{1}{2.19}+...+\frac{1}{1984.2000}\)
\(=\frac{1}{16}\left(\frac{16}{1.17}+\frac{16}{2.18}+...+\frac{16}{1984.2000}\right)\)
\(=\frac{1}{16}\left(1-\frac{1}{17}+\frac{1}{2}-\frac{1}{18}+...+\frac{1}{1984}-\frac{1}{2000}\right)\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{1984}\right)\right]-\left[\frac{1}{17}+\frac{1}{18}+...+\frac{1}{2000}\right]\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{16}\right)+\left(\frac{1}{17}+\frac{1}{18}+...+\frac{1}{1984}\right)-\left(\frac{1}{17}+\frac{1}{18}+...+\frac{1}{1984}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+...+\frac{1}{2000}\right)\right]\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{16}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+...+\frac{1}{2000}\right)\right]\)
Vậy A = B
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\(A=\left(1985\cdot1987-1\right):\left(1980+1985\cdot1986\right)\)
\(A=3944194\div3944190\)
ko chia hết nên sẽ bằng 1,4 lớn hơn 1
\(\Rightarrow A>1\)
1985x1987-1/1980+1985x1986=1985x1986+1985-1/1980+1985x1986
=1985x1986+1984/1980+1985x1986.Vì 1985x1986+1984>1980+1985x1986
suy ra 1985x1987-1/1980+1985x1986>1
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Ta có:
a) 203874 = (2032)437 = (...9)437 = .....9
b) 1682018 = 1682016. 1682 = (1684)504 . (...4) = (...6)504 . (...4) = (...6) . (....4) = .....4
c) 99932019 - 44472017 = 99932018 . 9993 - 44472016 . 4447 = (99932)1009 . 3 - (44472)1008 . 4447 = (....9)1009 . 3 - (....9)1008 . 4447 = ...9 . 3 - ....9 . 7 = ....7 - .....3 = ....4
d) 321985 + 141990 = 321984 . 32 + (142)995 = (324)496 . 32 + (....6)995 = (....6)496 . 32 + (....6) = (....6) . 32 + (....6) = .....2 + ...6 = ....8
\(a;203^{874}=\left(203^4\right)^{218}\times203^2=...1\times...9=...9\)
\(b;168^{2018}=\left(168^4\right)^{504}\times168^2=...6\times...4=...4\)
\(c;9993^{2019}-4447^{2017}=\left(9993^4\right)^{504}\times9993^3-\left(4447^4\right)^{504}\times4447\)
\(=...1\times...7-...1\times...7=...0\)
\(d;32^{1985}+14^{1990}=\left(32^4\right)^{496}\times32+\left(14^2\right)^{995}\)
\(=...6\times32+...6=...2+...6=...8\)
sailor moon mà
cậu tích xem phim sale moon phải không đúng thì nhấn nhé