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YẾN ƠI TUI BẠN BÀ NÈ
NHƯNG TUI HỔNG PHẢI LỚP 6 THÔNG CẢM NHA
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a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
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a. \(1\frac{5}{7}\)-\(\frac{9}{7}\)*\(\frac{16}{9}\)
=\(\frac{12}{7}\)-\(\frac{16}{7}\)
=\(\frac{-4}{7}\)
b. \(\frac{-5}{8}\):\(\frac{1}{4}\)-\(\frac{6}{13}\)*4+\(\frac{3}{8}\)
=\(\frac{-5}{8}\cdot\)4-\(\frac{6}{13}\)*4+\(\frac{3}{8}\)
=4*(\(\frac{-5}{8}\)-\(\frac{6}{13}\))+\(\frac{3}{8}\)
=4*\(\frac{-113}{104}\)+\(\frac{3}{8}\)
=\(\frac{-113}{26}\)+\(\frac{3}{8}\)
=\(\frac{-413}{104}\)
c.( \(\frac{3}{8}\)+\(\frac{-1}{4}\)-\(\frac{5}{12}\)):\(\frac{1}{3}\)
=\(\frac{-7}{24}\)*3
=\(\frac{-7}{8}\)
Học tốt
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a. \(\frac{2}{3}+\frac{1}{3}.\left(\frac{-4}{9}+\frac{5}{6}\right):\frac{7}{12}\)
\(=1.\frac{7}{12}:\frac{7}{12}\)
\(=1\)
b.
\(\frac{5}{9}.\frac{8}{11}+\frac{5}{9}.\frac{9}{11}-\frac{5}{9}.\frac{6}{11}\)
\(=\frac{5}{9}.\left(\frac{8}{11}+\frac{9}{11}-\frac{6}{11}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
Tk mk nha!
b) \(=\frac{5}{9}.\left(\frac{8}{11}+\frac{9}{11}-\frac{6}{11}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
a) 15, 37 – 12, 37) . 0,12 = 3. 0,12 = 0,36
b ) 6 5 12 : 2 3 4 + 11 1 4 . 1 3 − 1 5 = 77 12 : 11 4 + 45 4 . 2 15 = 77 33 + 3 2 = 23 6 c ) 5 6 : 0,125 − 2 1 4 − 0,6 . 10 11 = 5 6 : 1 8 − 9 4 − 3 5 . 10 11 = 155 11 d ) 1,4. 15 19 − 4 5 + 2 3 : 2 1 5 = 7 5 . 15 19 − 22 15 : 11 5 = 21 19 − 2 3 = 25 57 e ) ( − 1,2 ) . − 3 24 + 0,4 − 1 4 15 : 1 2 3 = − 6 5 . − 3 24 + 2 5 − 19 15 : 5 3 = − 37 100 f ) 1 13 15 .0,75 − 11 20 + 25 % = 28 15 . 3 4 − 11 20 + 1 4 = 3 5