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áp dụng tc \(\frac{a}{b}< 1\Rightarrow\frac{a+m}{a+m}< 1\left(m\in N\right)\)
Ta có: \(B=\frac{15^{16}+1}{15^{17}+1}< \frac{15^{16}+1+14}{15^{17}+1+14}\)\(=\frac{15^{16}+15}{15^{17}+15}=\frac{15.\left(15^{15}+1\right)}{15.\left(15^{16}+1\right)}=\frac{15^{15}+1}{15^{16}+1}\)
\(\Rightarrow B< A\)
\(A=\frac{15^{15}+1}{15^{16}+1}\)
\(\Rightarrow15A=\frac{15^{16}+15}{15^{16}+1}\)
\(\Rightarrow15A=\frac{15^{16}+1+14}{15^{16}+1}\)
\(\Rightarrow15A=\frac{15^{16}+1}{15^{16}+1}+\frac{14}{15^{16}+1}\)
\(\Rightarrow15A=1+\frac{14}{15^{16}+1}\)
\(B=\frac{15^{16}+1}{15^{17}+1}\)
\(\Rightarrow15B=\frac{15^{17}+15}{15^{17}+1}\)
\(\Rightarrow15B=\frac{15^{17}+1+14}{15^{17}+1}\)
\(\Rightarrow15B=\frac{15^{17}+1}{15^{17}+1}+\frac{14}{15^{17}+1}\)
\(\Rightarrow15B=1+\frac{14}{15^{17}+1}\)
Vì \(\frac{14}{15^{17}+1}< \frac{14}{15^{16}+1}\) nên \(15B< 15A\)
Vậy B < A
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Ta có công thức \(\frac{a}{b}<1\)thì\(\frac{a}{b}<\frac{a+n}{b+n}\)
\(B=\frac{15^{16}+1}{15^{17}+1}<\frac{15^{16}+1+14}{15^{17}+1+14}=\frac{15^{16}+15}{15^{17}+15}=\frac{15\left(15^{15}+1\right)}{15\left(15^{16}+1\right)}=\frac{15^{15}+1}{15^{16}+1}=A\left(1\right)\)
từ (1) \(\Leftrightarrow A>B\)
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a, Vì A, B < 1
\(A=\frac{15^{16}+1}{15^{17}+1}< \frac{15^{16}+1+14}{15^{17}+1+14}=\frac{15^{16}+15}{15^{17}+15}=\frac{15\left(15^{15}+1\right)}{15\left(15^{16}+1\right)}=\frac{15^{15}+1}{15^{16}+1}\)
b, \(B=\frac{2018^{2018}+1}{2018^{2019}+1}< 1< \frac{2018^{2019}+1}{2018^{2018}+1}=A\)
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Ta có:
\(125^{36}=\left(5^3\right)^{36}=5^{108}=5^{60}.5^{48}=5^{60}.\left(5^2\right)^{24}\)
\(=5^{60}.25^{24}\)
\(16^{24}.625^{15}=16^{24}.\left(5^4\right)^{15}=16^{24}.5^{60}\)
Vì \(25>16\) nên \(25^{24}>16^{24}\)=> \(5^{60}.25^{24}>5^{60}.16^{24}\)
Vậy \(125^{36}>16^{24}.625^{15}\)
T**k mik nhé!
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315= 35.3= ( 3 3) 5 = 275
1620= 16 5.4 =(164)5 = 655365
Vì 655365 > 275 nên 315 < 1620
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phân số đầu gọi là A
phân số thứ 2 là B
ta có: \(13A=\frac{13^{16}+13}{13^{16}+1}=1+\frac{13}{13^6+1}\)
\(13B=\frac{3^{17}+13}{13^{17}+1}=1+\frac{13}{13^7+1}\)
vì \(13^{16}+1< 13^{17}+1\)nên 13A>13B => A>B
giải thích thêm nhé
phân số nào có mẫu lớn hơn tử thì phân số đó bé hơn
trong trường hợp trên khi đã rút gọn nó ra rồi thì chỉ cần so sánh mẫu thôi vì tử đều là 13
Vì \(\frac{13^{16}+1}{13^{17}+1}< 1\)
\(\Rightarrow\frac{13^{16}+1}{13^{17}+1}< \frac{13^{16}+1+12}{13^{17}+1+12}=\frac{13^{16}+13}{13^{17}+13}=\frac{13\left(13^{15}+1\right)}{13\left(13^{16}+1\right)}=\frac{13^{15}+1}{13^{16}+1}\)
Vậy \(\frac{13^{15}+1}{13^{16}+1}>\frac{13^{16}+1}{13^{17}+1}\)
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A=10^15+1/10^16+1
=>10A=1+9/10^16+1
B=10^16+1/10^17+1
=>10B=1+9/10^17+1
=>10A>10B=>A>B
Vậy:A>B
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15mu16>16mu15 kkk to nh a