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a) \(\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)=\left(-5\right)^5\)
b)\(\left(-2\right)\left(-2\right)\left(-2\right)\left(-3\right)\left(-3\right)\left(+3\right)=\left(-2\right)^3\cdot\left(-3\right)^2\cdot3=\left(-2\right)^3\cdot3^3\)
c) \(\left(-7\right)\cdot7\cdot5\cdot\left(-5\right)\left(-5\right)=\left(-7^2\right)\cdot\left(-5\right)^3\)
d) \(\left(-8\right)\left(-3\right)3\cdot125=\left(-2^3\right)\cdot\left(-3^2\right)\cdot5^3\)
e) \(27\cdot\left(-2\right)3\left(-7\right)\cdot49=3^4\cdot\left(-2\right)\cdot\left(-7^3\right)\)
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a: \(\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)=\left(-5\right)^5\)
b: \(\left(-2\right)\cdot\left(-2\right)\cdot\left(-2\right)\cdot\left(-3\right)\cdot\left(-3\right)\cdot\left(+3\right)=\left(-2\right)^3\cdot3^3\)
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126 = 2.32.7
126 = 21.32.71
⇒ a = 1; b = 2; c = 1
Vậy a + b + c = 1 + 2 + 1 = 4
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\(a,\left(-7\right)^6\)
\(b,\left(-4\right)^3.\left(-5\right)^3=\left[\left(-4\right).\left(-5\right)\right]^3=20^3\)
125 . 217 = 53 . (3 .7)7 =53 . 37 .77