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A = (x5 - x2) + (x2 + x + 1) + (x4 - x) = x2.(x3 - 1) + (x2 + x+1) + x.(x3 - 1)
A = x2.(x -1).(x2 + x+ 1) + (x2 + x+1) + x.(x -1).(x2 + x+1) = (x2 + x+1).[x2.(x -1) + 1+ x.(x-1)]
A = (x2 + x+1) .(x3 - x + 1)
a/ x4 +5x3 +10x-4
=(x4- 4)+(5x3 + 10x)
=(x2+2) (x2-2) + 5x(x2 +2 )
=(x2+2)(x2 -2 +5x)
b/x5 - x4 +x3 -x2 +x-1
=x4(x-1)+x3(x-1)+(x-1)
=(x-1)(x4+x3+1)
= x^4 + 7x^3 - x^3 - 7x^2 - 11x^2 - 77x - 4x - 28
= x^3 ( x + 7 ) - x^2 ( x+ 7 ) - 11x( x+ 7 ) - 4 ( x+ 7 )
= ( x+ 7 )( x^3 -x^2- 11x - 4 )
Tự làm tiếp
a)\(x^2+2x+1=\left(x+1\right)^2\)
b)\(1-2y+y^2=\left(1-y\right)^2\)
hơ hơ ~ dễ thế này cơ mà!
a.x2+2x+1=x2+2x+12=(x+1)2=(x+1)*(x+1)
b.1-2y+y2=12-2y+y2=(y-1)2=(y-1)*(y-1)
a/ \(x^5+x+1=\left(x^5+x^4+x^3\right)+\left(-x^4-x^3-x^2\right)+\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)
c/ \(x\sqrt{x}-3x+4\sqrt{x}-2=\left(x\sqrt{x}-x\right)+\left(-2x+2\sqrt{x}\right)+\left(2\sqrt{x}-2\right)\)
\(=\left(\sqrt{x}-1\right)\left(x-2\sqrt{x}+2\right)\)
x - y + x2 - y2
= (x - y) + (x2 + y2)
= (x - y) + (x + y) (x - y)
= (x - y) (x + y + 1)
#Hoc tot!!!
\(x^7+x^5+1\)
\(=x^7+x^6+x^5-x^6-x^5-x^4+x^5+x^4+x^3-x^3-x^2-x\) \(+x^2+x+1\)
\(=\left(x^7+x^6+x^5\right)-\left(x^6+x^5+x^4\right)+\left(x^5+x^4+x^3\right)-\) \(\left(x^3+x^2+x\right)+\left(x^2+x+1\right)\)
\(=x^5\left(x^2+x+1\right)-x^4\left(x^2+x+1\right)+x^3\left(x^2+x+1\right)-x\left(x^2+x+1\right)\) \(+\left(x^2+x+1\right)\)
\(=\)\(\left(x^5-x^4+x^3-x+1\right)\left(x^2+x+1\right)\)
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