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(x2+2x)2-2(x2+2x)-3
=(x2+2x)(x2+2x-2)-3
Đặt t=x2+2x ta có:
t(t-2)-3=t2-2t-3
=(t-3)(t+1)=(x2+2x-3)(x2+2x+1)
=(x-1)(x+3)(x+1)2
(x^2+2x)^2-2(x^2+2x)-3
=(x^2+2x)(x^2+2x-2)-3
=(x^2+2x)(x^2+2x-5)
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bạn có thể bấm nghiệm bằng máy tính rồi tách theo nghiệm
x3+2x2-2x-12=x3-2x2+4x2-8x+6x-12
=x2.(x-2)+4x.(x-2)+6.(x-2)
=(x-2)(x2+4x+6)
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1.2x^2+x-6=2x^2+4x-3x+6=(2x^2+4x)-(3x+6)=2x(x+2)-3(x+2)=(x+2)(2x-3)
2.x^3-9x^2+14x
=x*(x^2-9x+14)
=x*(x^2-7x-2x+14)
=x*((x^2-7x)-(2x-14))
=x*(x(x-7)-2(x-7))
=x*((x--7)(x-2))
=x*(x-7)(x-2)
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\(2x^3-35x+75\)
\(=2x^3-50x+15x+75\)
\(=2x\left(x^2-25\right)+15\left(x+5\right)\)
\(=2x\left(x-5\right)\left(x+5\right)+15\left(x+5\right)\)
\(=\left(x+5\right)\left(2x^2-10x+15\right)\)
TK NKA !!!!
= x3 - x2 + x2 - x + 3x - 3
= x2(x - 1) + x(x - 1) + 3(x - 1)
= (x - 1) ( x2 + x + 3)
\(x^3+2x-3\)
\(=x^3-x^2+x^2-x+3x-3\)
\(=x^2\left(x-1\right)+x\left(x-1\right)+3\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2+x+3\right)\)
hk tốt
^^