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help me !! mik cần giải bài này gấp các bn giải nhanh dùm mik đi
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a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)
(\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)
- \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)
\(x\) = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))
\(x=\) - \(\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)
3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)
3\(x\) - 3,7 = - \(\dfrac{19}{2}\)
3\(x\) = - \(\dfrac{19}{2}\) + 3,7
3\(x\) = - \(\dfrac{29}{5}\)
\(x\) = - \(\dfrac{29}{5}\) : 3
\(x\) = - \(\dfrac{29}{15}\)
Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\)
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6x - 5 = 613
=> 6x = 613 + 5 = 618
=> x = 618 : 6 = 103.
0 : x = 0 => x là số nguyên nhưng x phải khác 0.
(x - 47) - 115 = 0
=> x - 47 = 115
=> x = 115 + 47 = 162
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\(5\frac{8}{7}\div x-\frac{4}{17}\div x+3\frac{1}{7}\div17\frac{1}{3}=\frac{4}{11}\)
\(\Leftrightarrow\frac{43}{7}\div x-\frac{4}{17}\div x+\frac{22}{7}\div\frac{52}{3}=\frac{4}{11}\)
\(\Leftrightarrow\left(\frac{43}{7}-\frac{4}{17}\right)\div x+\frac{33}{182}=\frac{4}{11}\)
\(\Leftrightarrow\frac{703}{119}\div x+\frac{33}{182}=\frac{4}{11}\)
\(\Leftrightarrow\frac{703}{119}\div x=\frac{365}{2002}\)
\(\Leftrightarrow x=32,40257857\)( Casio nó k hiện phân số nên mình viết tạm vầy nhé :)
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a, 1 - 2 - 3 + 4 + 5 + 6 - 7 + ... + 1996 + 1997 - 1998 - 1999 + 2000 + 2001
= ( 1 - 2 - 3 + 4 ) + ( 5 - 6 - 7 + 8 ) + ... +( 1993 - 1994 - 1995 + 1996 ) + ( 1997 - 1998 - 1999 + 2000 ) + 2001
= 0 + 0 + ... + 0 + 0 + 2001
= 2001
b, 1 - 3 + 5 -7 + ...+ 2001 - 2003 + 2005
= ( 1 -3 ) + ( 5 - 7 ) + ... + ( 2001 - 2003 ) + 2005
= -2 + (-2 )+ ... + (-2) + 2005
Có 501 số ( - 2 )
= ( - 2 ) . 501 + 2005
= -1002 + 2005
= 1003
P/s : Tham khảo ( Chép đầu bài thôi cũng sai )
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bạn đã kiểm tra kĩ chưa vậy?mình đọc đề câu B mà loạn não luôn á;-;
Ta có: (x - 1) : 2 + 1 (số hạng)
(x + 1) [(x - 1) : 2 + 1] = 72
(x + 1) (x - 1) : 2 + (x + 1) = 72
(x + 1) (x - 1) + 2 (x + 1) = 144
(x + 1) (x + 1) = 144
Mà 144 = 12 . 12
=> x + 1 = 12 => x = 12 - 1 => x = 11
Vậy x = 11
= 1+3+5+...+x=36
=> = x - 1 : 2 + 1 = 36
= ( 36 - 1 ) . 2 + 1 = 71