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d, \(\dfrac{-31}{240}\) e , \(\dfrac{43}{72}\) g, \(\dfrac{-5}{36}\)
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\(\dfrac{-5}{21}+\dfrac{-2}{21}+\dfrac{8}{24}=\dfrac{-7}{21}+\dfrac{8}{24}=\dfrac{-1}{3}+\dfrac{1}{3}=\dfrac{0}{3}=0\)\(\dfrac{-3}{7}+\dfrac{5}{13}+\dfrac{-4}{7}=(\dfrac{-3}{7}+\dfrac{-4}{7})+\dfrac{5}{13}=\dfrac{-7}{7}+\dfrac{5}{13}=\left(-1\right)+\dfrac{5}{13}=\dfrac{-13}{13}+\dfrac{5}{13}=\dfrac{-8}{13}\)
a) \(\dfrac{-3}{7}+\dfrac{5}{13}+\dfrac{-4}{7}=\left(\dfrac{-3}{7}+\dfrac{-4}{7}\right)+\dfrac{5}{13}\)
= -1+\(\dfrac{5}{13}\)
=\(\dfrac{-13}{13}+\dfrac{3}{13}\)
=\(\dfrac{-8}{13}\)
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\(a,\frac{a}{-b}=\frac{-a}{b}vìa.b=-a.\left(-b\right)\)
\(b,\frac{-a}{-b}=\frac{a}{b}vì-a.b=-b.a\)
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\(\frac{3}{-4}=\frac{-3}{4};\frac{-5}{-7}=\frac{5}{7};\frac{2}{-9}=\frac{-2}{9};\frac{-11}{-10}=\frac{11}{10}\)
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C=c.3/4+c.5/6-c.19/12
=c.(3/4+5/6-19/12)
=c.0
=0
Vậy C=0
Thay c = 2002/2003 vào, ta có:
C = 2002/2003 . 3/4 + 2002/2003 . 5/6 - 2002/2003 . 19/12
C = 2002/2003 . (3/4 + 5/6 - 19/12)
C = 2002/2003 . (9/12 + 10/12 - 19/12)
C = 2002/2003 . 0
C = 0
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a , \(\frac{3.5}{8.24}=\frac{3.5}{8.8.3}=\frac{5}{64}\)
b , \(\frac{2.14}{7.8}=\frac{2.2.7}{7.2.2.2}=\frac{1}{2}\)
c, \(\frac{3.7.11}{22.9}=\frac{3.7.11}{2.11.3}=\frac{7}{6}\)
d , \(\frac{8.5-8.2}{16}=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{3}{2}\)
e , \(\frac{11.4-11}{2-13}=\frac{11.\left(4-1\right)}{-11}=\frac{11.3}{-11}=-3\)
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a) \(\frac{3\cdot5}{8\cdot24}=\frac{5}{8\cdot8}=\frac{5}{64}\)
b) \(\frac{2\cdot14}{7\cdot8}=\frac{14}{7\cdot4}=\frac{2}{4}=\frac{1}{2}\)
c) \(\frac{3\cdot7\cdot11}{22\cdot9}=\frac{7}{2\cdot3}=\frac{7}{6}\)
d) \(\frac{8\cdot5-8\cdot2}{16}=\frac{8\cdot3}{16}=\frac{24}{16}=\frac{3}{2}\)
e) \(\frac{11\cdot4-11}{2-13}=\frac{11\cdot3}{2-13}=\frac{33}{-11}=-3\)
Giải.
a) Vì -11 < -10 < -9 < -8 < -7 nên:
b) Quy đồng mẫu các phân số ta có:![This is the rendered form of the equation. You can not edit this directly. Right click will give you the option to save the image, and in most browsers you can drag the image onto your desktop or another program.](http://latex.codecogs.com/gif.latex?%5Cfrac%7B-12%7D%7B36%7D%3C%5Cfrac%7B...%7D%7B36%7D%3C%5Cfrac%7B...%7D%7B36%7D%3C%5Cfrac%7B-9%7D%7B36%7D.)
Vì -12 < -11 < -10 < -9 nên ta có: