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\(D=2+2.2+2.2.2+2.2.2.2.2.2.2.2.2.2\)
=\(2+2^2+2^3+2^{10}\)
=\(2+4+8+1024=1038\)
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Ta có : 2A = \(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^9}\)
2A A = \(\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^9}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{10}}\right)\)
A = \(1-\frac{1}{2^{10}}=\frac{1023}{1024}\)
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+...+\frac{1}{2^{10}}=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{1024}=\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{512}-\frac{1}{1024}\)
\(A=\frac{1}{2}-\frac{1}{1024}=\frac{511}{1024}\)
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Bài làm
36:9+22.3-10
= 4 + 4.3 - 10
= 4 + 12 - 10
= 6
# Chúc bạn học tốt #
~ Yêu bạn, hồ thị yến ~
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Chứng tỏ:2+23+24+.......+210 chia hết cho 3 và 31.
với
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ta xét :\(2^4-4^2=2^4-\left(2^2\right)^2=2^4-2^4=0\)
=> giá trị biểu thức =0
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D=24.2015-24.2.(5.2).102+25
D=24.2015-24.2.103+25
D=24.2015-24.200+25
D=24(2015-2000)+25
D=16.15+25
D=240+25
D=265
D= \(2^4.2015-16.5.2^2.10^2+5^2\)
D= \(16.2015-16.5.4.100+25\)
D= \(16.2015-16.2025\)
D=\(16.\left(2015-2025\right)\)
D= \(16.\left(-10\right)\)
D= -160
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E= 29.26:213 = 29+6-13 = 22 = 4
F=35.27.26 = 35.33.26 = 38.26 = 419904
G=64.210 :214 = 26.210 :214 = 26+10-14 = 22 = 4
F=32.128:210 = 25.27:210 = 25+7-10 = 22 = 4
\(D=2+2^2+2^3+...+2^{10}\)
\(\Rightarrow2D=2^2+2^3+2^4+...+2^{11}\)
\(\Rightarrow2D-D=2^2+2^3+2^4+...+2^{11}-2-2^2-2^3-...-2^{10}\)
\( \Rightarrow D=2^{11}-2\)