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a) 6,75kg x 3 =20,25kg
b) 7,14m^2 x 5= 35,7 m^2
c) 9,26dm^3 x 10= 92,6 dm^3

a) 6,75kg + 6,75kg + 6,75kg = 6,75kg x 3 = 20,25kg
b) 7,14 m2 + 7,14 m2 + 7,14 m2 = 7,14 m2 x 3 = 21,42 m2
c) 9,26 dm3 x 9 + 9,26 dm3 = 9,26 dm3 x ( 9 + 1 ) = 9,26 dm3 x 10 = 92,6 dm3

\(3\frac{2}{5}=\frac{3\cdot5+2}{5}=\frac{17}{5}\)
\(2\frac{1}{7}=\frac{2\cdot7+1}{7}=\frac{15}{7}\)
\(8\frac{1}{6}=\frac{8\cdot6+1}{6}=\frac{49}{6}\)
\(2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{5}{2}\)
\(3\frac{2}{5}\cdot2\frac{1}{7}=\frac{17}{5}\cdot\frac{15}{7}=\frac{51}{7}\)
\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{49}{6}\cdot\frac{2}{5}=\frac{49}{15}\)

1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
9,26dm3 x 9 + 9,26dm3 = 9,26dm3 x (9 + 1) = 9,26dm3 x 10 = 92,6dm3