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2 tháng 3 2018

a,1/40

b,1/100

9 tháng 6 2017

\(a,\left(\dfrac{7}{20}+\dfrac{11}{15}-\dfrac{15}{12}\right):\left(\dfrac{11}{20}-\dfrac{26}{45}\right).\)

\(=\left(\dfrac{21}{60}+\dfrac{44}{60}-\dfrac{75}{60}\right):\left(\dfrac{99}{180}-\dfrac{104}{180}\right).\)

\(=\left(\dfrac{65}{60}-\dfrac{75}{60}\right):\left(-\dfrac{5}{180}\right).\)

\(=-\dfrac{10}{60}:\left(-\dfrac{5}{180}\right).\)

\(=-\dfrac{1}{6}:\left(-\dfrac{1}{36}\right).\)

\(=-\dfrac{1}{6}.\left(-36\right).\)

\(=\dfrac{-1.\left(-36\right)}{6}=\dfrac{36}{6}=6.\)

Vậy......

\(b,\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}.\)

\(=\dfrac{5\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}{8\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}:\dfrac{15\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}{16\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}.\)

\(=\dfrac{5}{8}:\dfrac{15}{16}.\)

\(=\dfrac{5}{8}.\dfrac{16}{15}=\dfrac{5.16}{8.15}=\dfrac{1.2}{1.3}=\dfrac{2}{3}.\)

Vậy......

c, (làm tương tự câu b).

~ Học tốt!!! ~

5 tháng 12 2023

a) $371+731-271-531$

$=(371-271)+(731-531)$

$=100+200$

$=300$

b) $57+58+59+60+61-17-18-19-20-21$

$=(57-17)+(58-18)+(59-19)+(60-20)+(61-21)$

$=40+40+40+40+40$

$=40\cdot5$

$=200$

c) $9-10+11-12+13-14+15-16$

$=(9-10)+(11-12)+(13-14)+(15-16)$

$=-1+(-1)+(-1)+(-1)$

$=-1\cdot4$

$=-4$

$\text{#}Toru$

5 tháng 12 2023

thanks

16 tháng 3 2022

`Answer:`

a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)

\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)

\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)

\(=\frac{1}{6}-\frac{7}{12}\)

\(=-\frac{5}{12}\)

b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)

\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)

\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)

\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)

\(=\frac{5}{9}.\frac{-17}{5}\)

\(=-\frac{17}{9}\)

c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)

\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)

\(=\frac{77}{325}-1-\frac{2}{13}\)

\(=-\frac{452}{325}\)