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a) \(\frac{1}{2}\times x-3=6\)
=> \(\frac{1}{2}\times x=6+3\)
=> \(\frac{1}{2}\times x=9\)
=>\(x=9:\frac{1}{2}\)
=> \(x=18\)
b) \(2:x=\frac{2}{5}--\frac{1}{10}\)
=> \(2:x=\frac{2}{5}+\frac{1}{10}\)
=> \(2:x=\frac{1}{2}\)
=> \(x=2:\frac{1}{2}\)
=> \(x=4\)
c) \(25-\left(2\frac{1}{2}+x\right)=10\)
=> \(2\frac{1}{2}+x=25-10\)
=> \(\frac{5}{2}+x=15\)
=>\(x=15-\frac{5}{2}\)
=> \(x=\frac{25}{2}\)
d) \(\left(x-\frac{3}{4}\right)\times3-45:9=10\)
=> \(\left(x-\frac{3}{4}\right)\times3-5=10\)
=> \(\left(x-\frac{3}{4}\right)\times3=10+5\)
=> \(\left(x-\frac{3}{4}\right)\times3=15\)
=> \(\left(x-\frac{3}{4}\right)=15:3\)
=> \(\left(x-\frac{3}{4}\right)=5\)
=> \(x=5+\frac{3}{4}\)
=> \(x=\frac{23}{4}\)
\(a,\frac{1}{2}.x-3=6\Rightarrow\frac{x}{2}=9\Rightarrow x=18\)
\(b,2:x=\frac{2}{5}-\frac{1}{10}\Rightarrow\frac{2}{x}=\frac{9}{10}\Rightarrow x=\frac{2.10}{9}=\frac{20}{9}\)
\(c,25-\left(2\frac{1}{2}+x\right)=10\Rightarrow25-\frac{5}{2}+x=10\Rightarrow x=10+\frac{5}{2}-25=-\frac{25}{2}\)
\(d,\left(x-\frac{3}{4}\right).3-45:9=10\Rightarrow\left(x-\frac{3}{4}\right).3-5=10\Rightarrow\left(x-\frac{3}{4}\right).3=15\Rightarrow x-\frac{3}{4}=5\Rightarrow x=\frac{23}{4}\)

a) X = 15
b) X = 4
c ) X= 23
d) X= 11
( Chỉ là ý kiến riêng thôi nhé, nhận gạch đá )
a) \(\frac{6+x}{33}=\frac{7}{11}\)
=> (6 + x). 11 = 33.7
=> 66 + 11x = 231
=> 11x = 231 - 66
=> 11x = 165
=> x = 165 : 11
=> x = 15
b) 15/26 + x/13 = 46/52
=> x/13 = 23/26 - 15/26
=> x/13 = 4/13
=> x = 4
c) 121/27 x 54/11 < x < 100/21 : 25/126
=> 22 < x < 24
=> x = 23 (vì x là số tự nhiên)
d) 1 < 11/x < 12
=> 11/x \(\in\){2; 3; 4 ; ...; 11}
=> x \(\in\) {11/2; 11/3; ...; 1}
Vì x là số tự nhiên => x = 1

a) \(\frac{3}{5}+25-\frac{1}{5}=\left(\frac{3}{5}-\frac{1}{5}\right)+25=\frac{2}{5}+25=\frac{2}{5}+\frac{125}{5}=\frac{127}{5}\)
b) \(13\times3\times32,27+67,63\times39=39\times32,27+67,63\times39\)
\(=39\times\left(32,27+67,63\right)\)
\(=39\times99,9=3196,8\)
(Bạn xem lại đề nhé)
c) \(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times....\times\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times.....\times\frac{99}{100}\)
\(=\frac{1\times2\times3\times...\times99}{2\times3\times4\times....\times100}=\frac{1}{100}\)
a, \(\frac{3}{5}+25-\frac{1}{5}=\frac{127}{5}\)
b, \(\text{13 x 3 x 32,27 + 67,63 x 39 =}3896,1\)
............................
thank for watching me do homework

a)13x3x32,27+67,63x39
=39x32,27+67,63x39
=39x(32,27+67,63)
=39x100
=3900
b,= 1- [ 1/2 x 1/3 x1/4 x..... x 1/100 ]
=1/2 x 2/3 x 3/4 x .......x 99/100
= 1x2x3x......x99 / 2x3x4x...... x100 [ rút gọn ]
= 1/100

#)Giải :
a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8
\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )
\(\frac{2xX-4,36}{0,125}=\)0,25 x 32
\(\frac{2xX-4,36}{0,125}=8\)
\(2xX-4,36=8x0,125\)
\(2xX-4,36=1\)
\(2xX=1+4,36\)
\(2xX=5,36\)
\(X=5,36:2\)
\(X=2,68\)
#~Will~be~Pens~#
2+2=2x2
cau dau XxX=X+X
XxX=Xx2 VI \(\frac{1}{5}\)X\(\frac{1}{5}\)=\(\frac{1}{25}\)
NENX=\(\frac{1}{5}\)
X=2;X=0
CAU TIEp
XxX=\(\frac{1}{25}\)