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\(A=\frac{4^5.13+32^2.65}{4^4.104}=\frac{2^{10}.13+2^{10}.13.5}{2^8.2^3.13}=\frac{2^{10}.13.\left(1+5\right)}{2^{11}.13}=\frac{6}{2}=3\)
Vậy A = 3
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\(44.179+20^2-79.44\\ =44\left(179-79\right)+400\\ =44.100+400\\ =100\left(44+4\right)=4800\\ 3.4^2:\left[500-\left(7.35+125\right)\right]\\ =3.16:\left[500-370\right]\\ =48:130=\dfrac{24}{65}\\ 187+\left[921-\left(921+887\right)\right]\\ =187+921-921-887\\ =187-887=-700\)
44. 179+ 202 - 79.44 3. 42 : [500- (7.35+125)]
= 44. 179+400 - 79.44 = 3. 16: [500- (245+125)]
= 44. (179-79) +400 = 48: [ 500-370 ]
= 44. 100+400 = 48:130
= 4400+400 = 0, 369...
= 4800
187+ [ 921-( 921+887) = 187+ [921- 1808]
= 187+ (-159)
= 28
Thực hiện các phép tính sau:
a. (-9989)-(2008-9989)+(-192)
b. 44.179+202-79.44
c. 3.42:|500-(7.35+125)|
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\(9.5^x=\left(6+3\right).5^6\)
\(9.5^x=9.5^6\)
\(5^x=5^6\)
\(x=6\)
9.5 mũ x = ( 6 + 3 ) . 5 mũ 6
9.5 mũ 5 = 9.5 mũ 6
5 mũ x = 5 mũ 6
x = 6
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\(67,6:\dfrac{\dfrac{2}{5}x+3}{20+9.5}=\dfrac{132}{5}\)
\(\Rightarrow\dfrac{\dfrac{2}{5}x+3}{45}=67,6:\dfrac{132}{5}\)
\(\Rightarrow\dfrac{\dfrac{2}{5}x+3}{65}=\dfrac{169}{66}\)
\(\Rightarrow\left(\dfrac{2}{5}x+3\right).66=132.65\)
\(\Rightarrow\dfrac{2}{5}x+3=\dfrac{10985}{66}\)
\(\Rightarrow\dfrac{2}{5}x=\dfrac{10985}{66}-3=\dfrac{10787}{66}\)
\(\Rightarrow x=\dfrac{10787}{66}:\dfrac{2}{5}=\dfrac{53935}{132}\)
Vậy.........................
tinh hop li