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a/ 26176
b/ 8
c/472392
d/ Ko tính dc
Thấy mình đẳng cấp ko
Cho mình 10 k nhé
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\(D=\) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\) \(\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\) \(\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\) \(\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\) \(\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.4.2}{3^{28}.4}\)
\(=\) \(6\)
Chúc bn hok tốt ~
\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\frac{3^{28}.3.4.2}{3^{28}.4}=6\)
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Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
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Để tớ ghi đề giùm cho các bạn hiểu :
\(11^{21}+1\div11=121\)
\(4^{2x}+1=64\)
So sánh
\(10^{30}...2^{100}\)
\(2^{98}...9^{42}\)
bài 1
42x+1 = 64
=> 42x+1 = 43
=> 2x + 1 = 3
=> 2x = 2
=> x = 1
bài 2
1030 = ( 103 )10 = 100010
2100 = ( 210 )10 = 102410
=> 100010 < 102410
=> 1030 < 2100
298 = ( 27 )14 = 12814
942 = ( 93 )14 = 72914
=> 12814 < 72914
=> 298 < 942
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Ta có : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.8}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=3.2\)
\(\Rightarrow\) \(A=6\)
Vậy A = 6
♥...♥...♥ Chúc bn họk tốt ♥...♥...♥
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