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Ta có: 76 + 75 - 74 = 74 ( 72 + 7 - 1 ) = 74 . 55
suy ra chia hết cho 55
Ta có: 165 + 215 = ( 24 )5 + 215 = 220 + 215 = 215( 25 + 1) = 215 . 33
suy ra chia hết cho 33
thì ta cũng có \(7^6+7^5-7^4=7^4(7^2+7-1)\)\(=7^4.55\)
Vì 55chia hết cho 55\(=>\)\(7^4.55\) cũng chia hết ccho55
phần bên dưới cũng giải tương tự vậy thôi
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a, Đúng
b, Đúng
c, Sai
Bạn không có đề bài nên mình chỉ biết thế thôi!
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1a)
Có A=\(33^{44}=3^{44}\cdot11^{44}=\left(3^4\right)^{11}\cdot11^{44}\)
B= \(44^{33}=4^{33}\cdot11^{33}=\left(4^3\right)^{11}\cdot11^{33}\)
Vì \(3^4>4^3\)=> \(\left(3^4\right)^{11}>\left(4^3\right)^{11}\)
mà \(11^{44}>11^{33}\)
=> \(\left(3^4\right)^{11}+11^{44}>\left(4^3\right)^{11}+11^{33}\)
=>\(33^{44}>44^{33}\)
=> A > B
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a)76+75-74
=74(72+7-1)
=74*55 chia hết 55 (đpcm)
b)165+215
=(24)5+215
=220+215
=215(25+1)
=215*33 chia hết 33
c)817 - 279 - 913
=(34)7-(33)9-(32)13
=328-327-326
=326(32-3-1)
=326*5
=322*34*5
=322*81*5
=322*405 chia hết 405
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Lời giải:
$16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}=2^{15}(2^5+1)=33.2^{15}\vdots 33$
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S = 165 + 215
=> S = 220 + 215
=> S = 215.(25 + 1)
=> S = 215.33 \(⋮\)33 (đpcm)
Ta có \(S=16^5+2^{15}\)
\(S=\left(2^4\right)^5+2^{15}\)
\(S=2^{20}+2^{15}\)
\(S=2^{15}.\left(2^5+1\right)\)
\(S=2^{15}\left(32+1\right)\)
\(S=2^{15}.33⋮33\)
Vậy \(S=16^5+2^{15}\)chia hết cho 33
\(5^{20}:\left(5^{15}\times15+5^{15}\times10\right)=5^{20}:\left[5^{15}\left(15+10\right)\right]=5^{20}:\left(5^{15}.25\right)=5^{20}:\left(5^{15}.5^2\right)=5^{20}:5^{17}=5^3=125\)
\(33.\left(-55\right)+\left(-33\right).44-33=33.\left(-55\right)+33.\left(-44\right)-33=33\left[\left(-55\right)+\left(-44\right)-1\right]=33.\left(-100\right)=-3300\)
Đề bài yêu cầu gì đó em?