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Hai bài trên áp dụng công thức với khoảng cách là 2.
Ta có:
\(D=1+2^1+2^2+2^3+.....+2^{150}\)
\(\Rightarrow2D-D=\left(2+2^2+2^3+2^4+.....+2^{151}\right)-\left(1+2+2^2+2^3+....+2^{150}\right)\)
\(\Rightarrow D=2^{151}-1\)
\(E=1+4^1+4^2+....+4^{400}\)
\(\Rightarrow4E-E=\left(4+4^2+4^3+....+4^{401}\right)-\left(1+4^1+4^2+....+4^{400}\right)\)
\(\Rightarrow E\left(4-1\right)=4^{401}-1\Leftrightarrow E=\frac{4^{401}-1}{4-1}\)
Các câu còn lại làm tương tự
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b: \(=12\left(35\cdot173+27\right)\)
\(=12\cdot6082=72984\)
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- 22.32.5:22.3-32=3.5-32=15-9=6
- 2.52-22.32:32=2.(52-2)=2.(25-2)=46
3. 33.19-33.12=33.(19-12)=33.7=189
4. 3.52-16:22=3.52-24:22=3.25-4=75-4=71
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1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
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a)145-5[8^2-4:15]=145-5[64-4/15]=145-5.956/15=145-956/3=-521/3
b)13^2-3[15-16^2]=13^2-3.-241=169--723=892
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Giải: (^ là mũ)
a) 3^8 : 3^4 + 2^2 . 2^3
= 6561 : 81 + 4 . 8
= 81 + 32
= 113
Mấy câu sau bn làm tương tự nhé!
b: \(=2^{12}\cdot3^4\cdot\dfrac{3^{10}}{3^{12}\cdot2^{12}}=3^2=9\)
c: \(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot2\cdot3}=\dfrac{3^2}{3}=3\)
d: \(=\dfrac{5^3\cdot3^6\cdot5^4\cdot2^8\cdot3^{16}\cdot2^2}{\left(2^2\cdot3^2\cdot5\right)^5}=\dfrac{5^{10}\cdot3^{22}\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=3^{12}\cdot5^5\)