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Trả lời:
a) \(4^{10}.8^{15}=\left(2^2\right)^{10}.\left(2^3\right)^{15}\)
\(=2^{20}.2^{45}\)
\(=2^{65}\)
\(a,4^{10}\cdot8^{15}=\left[2^2\right]^{10}\cdot\left[2\cdot2^2\right]^{15}=2^{20}\cdot2^{15}\cdot2^{30}=2^{20+15+30}=2^{65}\)
\(b,\frac{27^{16}}{3^{10}}=\frac{\left[3^3\right]^{16}}{3^{10}}=\frac{3^{48}}{3^{10}}=3^{48-10}=3^{38}\)
\(c,\frac{\left[2^9\cdot16+2^9\cdot34\right]}{2^{10}}=\frac{\left[2^9\left\{16+34\right\}\right]}{2^{10}}=\frac{2^9\cdot50}{2^{10}}=\frac{1}{2}\cdot50=25\)
\(d,\frac{3^4\cdot57-9^2\cdot21}{3^5}=\frac{3^4\cdot57-\left[3^2\right]^2\cdot21}{3^5}=\frac{3^4\cdot57-3^4\cdot21}{3^5}=\frac{3^4\left[57-21\right]}{3^5}=\frac{1}{3}\cdot36=12\)
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a, = 3^15.2^24+2^16.3^16.2^10
= 3^15.2^24+3^16.2^26
= 3^15.2^24.(1+3.2^2) = 3^15.2^24.13
b, = 2.3.3^18.2^21-3.7.3^15.2^23
= 2^22.3^19-2^23.3^16.7
= 2^22.3^17.(3^3-2.7) = 2^22.3^17.13
k mk nha
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A, B, C,... là tên của bài bạn nha
VD: A, 15+x=15
B, 16+14+14+14
\(\dfrac{2^{15}+2^8}{16^3+2^9}=\dfrac{2^8\left(2^7+1\right)}{2^{12}+2^9}=\dfrac{2^8\left(2^7+1\right)}{2^9\left(2^3+1\right)}=\dfrac{1}{2}\cdot\dfrac{43}{3}=\dfrac{43}{6}\)
\(\left(2^{15}+2^8\right):\left(16^3+2^9\right)=2^8\left(2^7+1\right):\left(2^{12}+2^9\right)=2^8\left(2^7+1\right):\left[2^8\left(2^4+2\right)\right]=\left(2^7+1\right):\left(2^4+2\right)=\dfrac{129}{18}=\dfrac{43}{6}\)