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a, Ta thấy A chia hết cho 7 (nguyên tố)
Có : 7^2;7^3;....;7^10 đều chia hết cho 49 mà 7 ko chia hết cho 49
=> A ko chia hết cho 49
=> A chia hết cho 7 (nguyên tố ) mà A ko chia hết cho 49=7^2
=> A ko phải là số cp
Tương tự câu a : b, b chia hết cho 11 (nguyên tố) nhưng ko chia hết cho 11^2 => b ko chính phương
c, Vì 10^10 có tận cùng là 0
=> c có tận cùng là 8
=> c ko chính phương
k mk nha
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a, (1-x)3 =27
<=> 1-X = 3
<=> x=-2
con b cau xem lai de nha dau "=" trong ngoac la gi
a) (1-x)3=27
(1-x)3 = 33
=> (1-x) = 3
x =1 - 3
x = -2
Vậy x = -2
Mik chỉ bt lm câu a thui
Chúc bạn hok tốt
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a)
\(4^{10}\cdot8^{15}=2^{20}\cdot2^{45}=2^{65}\)
b)
\(27^{16}\cdot9^{10}=3^{48}\cdot3^{20}=3^{68}\)
a) 410 . 815 = (22)10 . (23)15 = 220 . 245 = 265
b) 2716 . 910 = (33)16 .(32)10=348 . 320 = 368
c) \(\frac{2^{10}\cdot13+2^{10}\cdot65}{28\cdot104}=\frac{2^{10}\cdot13\cdot\left(1+5\right)}{2^5\cdot7\cdot13}=\frac{2^5\cdot6}{7}=\frac{192}{7}\)
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a ) \(4^{10}.8^{15}\)
\(=\left(2^2\right)^{10}.\left(2^3\right)^{15}\)
\(=2^{20}.2^{45}\)
\(=2^{65}\)
a)\(4^{10}.8^{15}=\left(2^2\right)^{10}.\left(2^3\right)^{15}=2^{2.10}.2^{3.15}=2^{20}.2^{45}=2^{65}\)
b)\(4^{15}.5^{30}=4^{15}.5^{2.15}=4^{15}.\left(5^2\right)^{15}=4^{15}.25^{15}=\left(4.25\right)^{15}=100^{15}\)
c)\(27^{16}.9^{10}=\left(3^3\right)^{16}.\left(3^2\right)^{10}=3^{3.16}.3^{2.10}=3^{48}.3^{20}=3^{68}\)
d)\(72^3.54^2=\left(8.9\right)^3.\left(27.2\right)^2=8^3.9^3.27^2.2^2=\left(2^3\right)^3.\left(3^2\right)^3.\left(3^3\right)^2.2^2=2^{3.3}.3^{2.3}.3^{3.2}.2^2\)
\(=2^9.3^6.3^6.2^2=2^{11}.3^{12}\)
P/S : Lớp 6 rồi tập làm quen dấu ''x'' thành dấu ''.'' đi bạn
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mình thiếu 1 câu hhi
b) {( 10 - 2 . 3 ) .5] + 2 -2 . 6 } : 2 + ( 4 . 5 ) 2
a) (3x-24)73=2.74
3x-24=2.7 (Chia cả hai vế cho 73)
3x-16=14
3x=30
X=10
b)[(10 -x).2+5] : 3 -2 =3
(20-2x+5):3=5
25-2x=15
2x=10
X=5
Bài 2
{[(32+1).10-(8:2+6)]:2}+55-(10:5)3
={(9+1).10-10]:2}+55-23
=[(10.10-10):2]+55-8
=(90:2)+55-8
=45+55-8
=100-8
=92
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a. 4^10.8^15=2^20.2^30=2^50
b. 4^15.5^30=2^30.5^30=10^30
c. 27^16:9^10=3^48:3^20=3^28
a) 410.815 = (22)10 . (23)15 = 220 . 245 = 220+45 = 265
b) 415.530 = 415.(52)15 = 415.2515 = (4.25)15 = 10015
c) 2716:910 = (33)16:(32)10 = 348:320 = 348-20 = 328
d) \(A=\frac{72^3.54^2}{108^4}=\frac{\left(8.9\right)^3.\left(6.9\right)^2}{\left(12.9\right)^2}=\frac{8^3.9^3.6^2.9^2}{12^2.9^2}=\frac{8^3.9^3.6^2}{12^2}\)
\(=\frac{\left(2^3\right)^3.9^3.6^2}{\left(2.6\right)^2}=\frac{2^9.9^3.6^2}{2^2.6^2}=\frac{2^9.9^3}{2^2}=\frac{2^7.9^3}{2^0}=2^7.9^3=93312\)
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2|x - 5| = 8
\(\Rightarrow\) |x - 5| = 4
\(\Rightarrow\) |x - 5| = \(\left\{{}\begin{matrix}4\\-4\end{matrix}\right.\)
\(\Rightarrow\) x = \(\left\{{}\begin{matrix}9\\1\end{matrix}\right.\)
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c) 2x+(15-(7-4)2)=24.3
2x+(15-32)=16.3
2x+(15-9)=48
2x+6=48
2x=48-6
2x=42
x=42:2
x=21
Vậy...
a, 17+(-x)=-16-(-34)
<=> 17+(-x)= - 50
=> -x= - 33
=> x= 33
b, x-40=9.(-5)+9
<=> x-40= -36
=> x= 4
c, 2x + [ 15 - ( 7 - 4 ) 2 ] = 24 . 3
<=> 2x+ [ 15- 32 ] = 48
<=> 2x+4=48
=>2x=44
=>x=22
d, 1125-10x-3 = 152 - 102
=> 1125 - 10x-3 = 125
=> 10x-3 = 1000
=> 10x-3= 103
=> x-3=3
=>x=6