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x2-2005x-2006 = 0
x2+1x -2006x-2006=0
x(x+1)-2006(x+1)=0
(x-20016)(x+1)=0
=> x=2006 hoặc =-1
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a. Nếu x>0=> 2004x<2005x
Nếu x=0=> 2004x=2005x
Nếu x<0=> 2004x>2005x
b.Nếu x<5=> ...
...
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A = 2005 x 2005 + 1 / 2005 x 2005 x 2005 - 1
A = 2005 x 2005 + 1 / 2005 x 2005 x 2005 - 1
A = \(\frac{2005+1}{2005x2005-1}\)
B = \(\frac{2005+1}{2005x2005-1}\)
=> A = B
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\(A=\frac{2005^{2005}+1}{2005^{2006}+1}\)
\(2005A=\frac{2005^{2006}+2005}{2005^{2006}+1}=\frac{2005^{2006}+1+2004}{2005^{2006}+1}=\frac{2005^{2006}+1}{2005^{2006}+1}+\frac{2004}{2005^{2006}+1}\)
\(B=\frac{2005^{2004}+1}{2005^{2005}+1}\)
\(2005B=\frac{2005^{2005}+2005}{2005^{2005}+1}=\frac{2005^{2005}+1+2004}{2005^{2005}+1}=\frac{2005^{2005}+1}{2005^{2005}+1}+\frac{2004}{2005^{2005}+1}\)
Vì \(\frac{2004}{2005^{2006}+1}<\frac{2004}{2005^{2005}+1}\)
Nên A<B
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2005x(Xx2006)=2005
=>Xx2006=2005:2005
=>Xx2006=1
=>X=1:2006
=>X=1/2006
Chúc bạn học giỏi nha!!!1
K cho mik vs nhé mọi người
2005 x ( X x 2006 ) = 2005
X x 2006 = 2005 : 2005
X x 2006 = 1
X = 1 : 2006
X = 1/2006