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Tìm x biết:
5) {x\(^2\) - [16\(^2\) - ( 8\(^2\) - 9 . 7)\(^3\) - 17 . 15 ]\(^3\) - 5 . 3 ]\(^3\) = 1
\(\left\{x^2-\left[16^2-\left(8^2-9.7\right)^3-17.15\right]^3-5.3\right\}^3=1\)
\(\left\{x^2-\left[256-\left(64-9.7\right)^3-17.15\right]^3-5.3\right\}^3=1\)
\(\left\{x^2-\left[256-1^3-255\right]^3-15\right\}^3=1\)
\(\left\{x^2-\left[255-255\right]^3-15\right\}^3=1\)
\(\left\{x^2-0^3-15\right\}^3=1\)
\(\left\{x^2-15\right\}^3=1\)
\(\left\{4^2-15\right\}^3=1\)
\(\Rightarrow x=4\)
5: \(\Leftrightarrow\left\{x^2-\left[256-\left(64-63\right)^3-255\right]^3-15\right\}^3=1\)
\(\Leftrightarrow\left\{x^2-15\right\}^3=1\)
\(\Leftrightarrow x^2-15=1\)
=>x=4 hoặc x=-4
5\(\dfrac{8}{17}\):x + (-\(\dfrac{1}{17}\)) : x + 3\(\dfrac{1}{17}\) : 17\(\dfrac{1}{3}\)= \(\dfrac{4}{17}\)
\(\dfrac{93}{17}\).\(\dfrac{1}{x}\) + (-\(\dfrac{1}{17}\)) .\(\dfrac{1}{x}\) +\(\dfrac{3}{17}\)= \(\dfrac{4}{17}\)
\(\dfrac{1}{x}\).\(\dfrac{92}{17}\)=\(\dfrac{1}{17}\)
\(\dfrac{1}{1.4}\)+\(\dfrac{1}{4.7}\)+\(\dfrac{1}{7.10}\)+...+\(\dfrac{1}{x.\left(x+3\right)}\)=\(\dfrac{6}{19}\)
a)\(x.6=-72\)
=> x = -12
b)\(\dfrac{7}{3}:x=\dfrac{-11}{45}\)
=> \(x=\dfrac{-105}{11}\)
c) \(x=\dfrac{-17}{9}\)
d)\(x=\dfrac{-3}{17}\)
e) \(x=\dfrac{7}{6}\)
f) \(\dfrac{39}{7}:x=11\)
=> \(x=\dfrac{39}{77}\)
a)
\(\dfrac{x}{8}=\dfrac{-9}{6}\)
=> x = \(\dfrac{8.\left(-9\right)}{6}\)
=> x = -12
15: \(\Leftrightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-63\right]^3-48\right\}=1\)
\(\Leftrightarrow x^2-48=1\)
=>x=7 hoặc x=-7
a: \(\Leftrightarrow-\dfrac{9}{46}+\dfrac{108}{46}-\dfrac{93}{23}:\left(\dfrac{13}{4}-\dfrac{5}{3}x\right)=1\)
\(\Leftrightarrow\dfrac{93}{23}:\left(\dfrac{13}{4}-\dfrac{5}{3}x\right)=\dfrac{53}{46}\)
\(\Leftrightarrow-\dfrac{5}{3}x+\dfrac{13}{4}=\dfrac{186}{53}\)
=>-5/3x=55/212
hay x=-33/212
c: \(\Leftrightarrow\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{x\left(x+3\right)}=\dfrac{18}{19}\)
\(\Leftrightarrow1-\dfrac{1}{x+3}=\dfrac{18}{19}\)
=>x+3=19
hay x=16