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a) \(=\left(\left(-\frac{1}{4}-\frac{5}{3}\right)+\frac{7}{33}\right)-\left(-\frac{15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)
\(=\left(-\frac{23}{12}+\frac{7}{33}\right)+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=\left(-\frac{23}{12}+\frac{15}{12}\right)+\left(\frac{9}{33}-\frac{6}{11}\right)+\frac{48}{49}\)
\(=-\frac{2}{3}-\frac{3}{11}+\frac{48}{49}\)
\(=\frac{65}{1617}\)
b) \(=\frac{11}{125}+\left(-\frac{17}{18}+\frac{4}{9}\right)+\left(-\frac{5}{7}+\frac{17}{14}\right)\)
\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)
\(=\frac{11}{125}\)
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\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)-\left(\frac{-15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=\left(\frac{-1}{4}-\frac{5}{3}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{6}{11}\right)+\frac{48}{49}\)
\(=\left(\frac{-3}{12}-\frac{20}{12}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{18}{33}\right)+\frac{48}{49}\)
\(=\left(\frac{-23}{12}+\frac{15}{12}\right)+\left(\frac{-11}{33}\right)+\frac{48}{49}\)
\(=\frac{-2}{3}+\left(\frac{-1}{3}\right)+\frac{48}{49}\)
\(=-1+\frac{48}{49}\)
\(=-\frac{1}{49}\)
Ùng hộ mk nha ^_-
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\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)\) \(-\left(-\frac{15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)
\(=\left(\frac{-1}{4}+\frac{7}{33}-\frac{55}{33}\right)\)\(+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)
\(=\left(\frac{-1}{4}-\frac{48}{33}\right)\)\(+\frac{8085}{6468}\)\(-\)\(\frac{3528}{6468}\)\(+\frac{6603}{6468}\)
\(=\frac{-75}{44}\)\(+\frac{930}{539}\)\(=\frac{45}{2156}\)
Bước đến nhà em bóng xế tà
Đứng chờ năm phút bố em ra
Lơ thơ phía trước vài con chó
Lác đác đằng sau chiếc chổi chà
Sợ quá anh chuồn quên đôi dép
Bố nàng ngoác mỏ đứng chửi cha
Phen này nhất quyết thuê cây kiếm
Trở về chém ổng đứt làm ba
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Số cây cam là:
120 : ( 2 + 3 ) x 2 = 48 (cây)
Số cây xoài là:
( 1 + 5 ) = 20 ( cây )
Số cây chanh là:
120 - ( 48 + 20 ) = 52 ( cây )
Đáp số : cam : 48 cây
xoài : 20 cây
chanh : 52 cây.
ai trên 10 điểm thì mình nha
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}-\left(-\frac{5}{4}\right)-\frac{6}{11}+\frac{48}{49}\)\(\frac{48}{49}\)
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{5}{4}-\frac{18}{33}+\frac{48}{49}\)
\(=\left(\frac{-1}{4}+\frac{5}{4}\right)+\left(\frac{7}{33}-\frac{18}{33}\right)-\frac{5}{3}\)\(+\frac{48}{48}\)
\(=1+\frac{-1}{3}-\frac{5}{3}+\frac{48}{49}\)
\(=1+\left(-2\right)+\frac{48}{49}\)
\(=-1+\frac{48}{49}\)
\(=\frac{-49}{49}+\frac{48}{49}\)
\(=\frac{-1}{49}\)
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\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)-\left(\frac{-5}{4}+\frac{6}{11}-\frac{48}{49}\right)=\left(\frac{-1}{4}-\frac{16}{11}\right)-\left(-\frac{31}{44}-\frac{48}{49}\right)=-\frac{1}{4}-\frac{16}{11}+\frac{31}{44}+\frac{48}{49}=-\frac{1}{49}\)
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\(=\dfrac{-1}{4}+\dfrac{7}{33}-\dfrac{5}{3}+\dfrac{5}{4}-\dfrac{6}{11}+\dfrac{48}{49}\)
\(=1+\dfrac{7}{33}-\dfrac{18}{33}-\dfrac{5}{3}+\dfrac{48}{49}\)
\(=\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{48}{49}=\dfrac{48}{49}-1=-\dfrac{1}{49}\)
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(-1/4+9/33-5/3)-(-5/4+6/11-48/49)
= -1/4+9/33-5/3+5/4-6/11+48/49
= -1/4+9/33+(-5/3)+5/4+(-6/11)+48/49
= 65/1617