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Theo mệnh giá trên diễn đàn, \(1coin\) có giá tương ứng \(=10xu\) hoặc \(1\) nghìn đồng.
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Gỉa sử: \(x^2=128\)
\(\Rightarrow\orbr{\begin{cases}x=\sqrt{128}\\x=-\sqrt{128}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=8\sqrt{2}\\x=-8\sqrt{2}\end{cases}}\)
\(\Rightarrow128=\left(\pm8\sqrt{2}\right)^2\)
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111112 = 123454321
CHÚC BN HỌC TỐT !
Thank you ..............!!
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Ta có :
\(A=3+3^2+3^3+3^4+3^5+3^6+...+3^{58}+3^{59}+3^{60}\)
\(\Rightarrow A=\left(3+3^2+3^3\right)+\left(3^4+3^5+3^6\right)+...+\left(3^{58}+3^{59}+3^{60}\right)\)
\(\Rightarrow A=3.\left(3^0+3^1+3^2\right)+3^4.\left(3^0+3^1+3^2\right)+...+3^{58}.\left(3^0+3^1+3^2\right)\)
\(\Rightarrow A=3.13+3^4.13+3^7.13+..+3^{58}.13\)
\(\Rightarrow A=\left(3+3^4+...+3^{58}\right).13⋮13\)
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1: Để C là số nguyên thì 2n+2-3 chia hết cho n+1
=>\(n+1\in\left\{1;-1;3;-3\right\}\)
=>\(n\in\left\{0;-2;2;-4\right\}\)
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x – (11 – x) = -48 + (-12 + x)
=> x−11+x=−48+−12+x
=> −11+x=−48−12
=> -11+x=-60
=> x=-49
Vậy x=-49
\(x-\left(11-x\right)=-48+\left(-12+x\right)\)
\(\Leftrightarrow x-11+x=-48-12+x\)
\(\Leftrightarrow x=-49\)
Vậy x = -49
\(112=2^4\cdot7\)
bằng 56 mũ 2