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Nữ hoàng cảm ơn nhưng vị thám tử tài ba có thể viết cách giải ra đc không ạ
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82.324
= (23)2 . (25)4
= 26.220 = 26+20
= 226
b) 815:97
= (92)5:97
= 910:97 = 910-7
= 93
a) 82 . 324 = ( 23)2 . ( 25)4 = 26 . 220 = 226
b) 815 : 97 = ( 34)5 . ( 32)7 = 320 . 314 = 334
Chúc học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(4^3.2^4\div\left(4^2.\frac{1}{32}\right)\)
\(=\left(2^2\right)^3.2^4\div\left(2^2\right)^2\div32\).
\(=2^{\left(2.3\right)}.2^4\div2^{\left(2.2\right)}\div2^5\)
\(=2^6.2^4\div2^4\div2^5\)
\(=2^{6+4-4-5}=2^1\)
b)\(\left(\frac{1}{5}\right)^5=\frac{1}{5^5}=\left|5^5\right|=5^{-5}\)
\(\frac{1}{125}=\frac{1}{5^3}=\left|5^3\right|=5^{-3}\)
c)\(\frac{4}{25}=\frac{2^2}{5^2}=\left(\frac{2}{5}\right)^2=0,4^2\)
\(\frac{-8}{125}=\frac{-2^3}{5^3}=\left(\frac{-2}{5}\right)^2=-0,4^3=0,4^{-3}\)
\(\frac{16}{625}=\frac{2^4}{5^4}=\left(\frac{2}{5}\right)^4=0,4^4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^5=3.3.3.3.3\)
\(6^2=6.6\)
\(5^4=5.5.5.5\)
\(2^2=2.2\)
\(7^3=7.7.7\)
cho mik đi
![](https://rs.olm.vn/images/avt/0.png?1311)
\(123^3:25^4\)
=\(5^{3\cdot3}:5^{2\cdot4}\)
=\(5^9:5^8\)
=\(5^{9-8}\)
=\(5^1=5\)
\(125^3:25^4\)
\(=\left(5^3\right)^3:\left(5^2\right)^4\)
\(=5^9:5^8\)
\(=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bạn ấy lm câu a rùi mik lm 3 câu còn lại nha
\(27^{16}:9^{10}\)
\(=3^{16}\cdot9^{16}:9^{10}\)
\(=9^8\cdot9^6=9^{14}\)
\(125^3:25^4\)
\(=5^3\cdot25^3:25^4\)
\(=5\cdot25\cdot25^3:25^4\)
\(=5\cdot25^4:25^4\)
\(=5\cdot1=5\)
\(24^4:3^4-32^{12}:16^{12}\)
\(=8^4\cdot3^4:3^4-2^{12}\cdot16^{12}:16^{12}\)
\(=8^4-2^{12}\)
\(=4096-4096\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(=x^{1.2.3....49.50}\)
b,\(\Rightarrow\)2Q\(=2+2^2+2^3+...+2^{50}\)
2Q-Q\(=2+2^2+2^3+...+2^{50}-1-2-2^2-...-2^{49}\)
Q\(=2^{50}-1\)
Q+1=\(2^{50}\)
Mà Q+1=\(2^n\)
\(2^{50}=2^n\Rightarrow n=50\)
\(25^6.125^3\)
\(=\left(5^2\right)^6.\left(5^3\right)^3\)
\(=5^{12}.5^9\)
\(=5^{12+9}\)
\(=5^{21}\)
Ủng hộ nha
256.1253=(52)6.(53)3=512.59=517