Bỏ dấu ngoặc rồi tính
(45+120)+(2012-120-45)
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a) ( 45 + 12 ) + ( 2012 - 120 - 45 )
= 45 + 12 + 2012 - 120 - 45
= 57 + 2012 - 120 - 45
= 2069 - 120 - 45
= 1976 - 45
= 1931
b) ( 1890 - 19 - 5 ) - ( 19 - 5 + 1890 )
= 1890 - 19 - 15 - 19 - 5 + 1890
= 1871 - 15 - 19 - 5 + 1890
= 1856 - 19 - 5 + 1890
= 1837 - 5 + 1890
= 1832 + 1890
= 3722
a, (45+12) + (2012-120-45)
= 45+12+2012-120-45
=(45-45) + 2012-120+12
=0+1892+12
=1904
b, (1890-19-5) - (19-5+1890)
=1890-19-5+19+5-1890
=(1890-1890)+(-19+19)+(-5+5)
=0
a) -(12+21-23)-(23-21+10)
=-12-21+23-23+21-12=-12-12=-24
b)(57-725)-(605-53)
=57-725-605+53=-1220
c)(55+45+45)-(15-55+45)
=55+45+45-15+55-45=110+45-15=140
-(12+21-23)-(23-21+10)
=-12-21+23-23+21-10
=(21-21)+(23-23)-(12+10)
=0+0-22=-22
(57-725)-(605-53)
=57-725-605+53
=(57+53)-(725+605)
=110-1330
=-1220
(55+45+45)- (15-55+45)
=55+45+45-15+55-45
=(45+55)+(55-15)+(45-45)
=100+40+0=140
365-(120+80-365-350)
=365-120-80+365+350 =(365+365)-(120+80)+350 =730-200+350 =530+350 =880\(1,=38-42+14-25+27+15=27\)
\(2,=12+21-23+21-10=21\)
\(3,=57-725-605+53=-1220\)
\(4,=55+45+15-15+55-45=110\)
a, 214+[120-(214+120)]=214+[120-214-120]
=214+120-214-120
=(214-214)+(120-120)
=0+0
=0
b,(-321)-[(-321+35)-235]=-321-[-321+35-235]
=-321-321-35+235
= (-321-321)-(35+235)
=0+270
=270
( 45 + 120 ) + ( 2012 - 120 - 45 )
= 45 + 120 + 2012 - 120 - 45
= ( 45 - 45 ) + ( 120 - 120 ) + 2012
= 0 + 0 + 2012
= 2012
(45 + 120) + (2012 - 120 - 45)
= 45 + 120 + 2012 - 120 - 45
= (45 - 45) + (120 - 120) + 2012
= 0 + 0 + 2012
= 2012