tính nhanh:3/5x11/13+2/5+3/5x2/13
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3/5 × 11/19 + 3/5 × 8/19 + 2/5
= 3/5 × (11/19 + 8/19) + 2/5
= 3/5 × 1 + 2/5
= 3/5 + 2/5
= 1
Ủng hộ mk nha ♡_♡

\(A=\frac{1}{3\times5}+\frac{3}{5\times11}+\frac{2}{11\times15}+\frac{3}{15\times21}\)
\(A=\frac{1}{2}\times\left(\frac{2}{3\times5}+\frac{6}{5\times11}+\frac{4}{11\times15}+\frac{6}{15\times21}\right)\)
\(A=\frac{1}{2}\times\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{21}\right)\)
\(A=\frac{1}{2}\times\left(\frac{1}{3}-\frac{1}{21}\right)\)
\(A=\frac{1}{2}\times\frac{2}{7}\)
\(A=\frac{1}{7}\)
A = \(\frac{1}{3.5}+\frac{3}{5.11}+\frac{2}{11.15}+\frac{3}{15.21}\)
A = \(\frac{1}{2}.\left(\frac{2}{3.5}+\frac{6}{5.11}+\frac{4}{11.15}+\frac{6}{15.21}\right)\)
A = \(\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{21}\right)\)
A = \(\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{21}\right)\)
A = \(\frac{1}{2}.\frac{2}{7}\)
A = \(\frac{1}{7}\)

a)\(\frac{3}{5}x\frac{7}{9}+\frac{11}{9}x\frac{3}{5}-\frac{3}{10}\)
\(=\frac{3}{5}x\left(\frac{7}{9}+\frac{11}{9}\right)-\frac{3}{10}\)
\(=\frac{3}{5}-\frac{3}{10}\)
\(=\frac{3}{5}\)
tương tự cho phần b nhé
chúc học tốt
=
a.\(\frac{9}{10}\)
b.\(\frac{20}{13}\)
cho mình nha, mình không có thời gian để giải công thức nên mình viết được chừng này thôi ^ ^


a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
Ta có: \(\frac35\cdot\frac{11}{13}+\frac25+\frac35\cdot\frac{2}{13}\)
\(=\frac35\left(\frac{11}{13}+\frac{2}{13}\right)+\frac25\)
\(=\frac35+\frac25=\frac55=1\)
\(\frac35\) x \(\frac{11}{13}\) + \(\frac25\) + \(\frac35\) x \(\frac23\)
= \(\frac35\) x ( \(\frac{11}{13}+\frac{2}{13}\) ) + \(\frac25\)
= \(\frac35\) x 1 + \(\frac25\)
= \(\frac35+\frac25\)
= 1