giúp em giải bài này với ạ
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TT
2
DT
Đỗ Thanh Hải
CTVVIP
24 tháng 5 2021
1 The meeting was canceled 3 days ago
2 She told me she was watching a film with her sister then
3 I admire the guitarist who is perfroming on the stage
4 Had it not been for Pauline's interest, the project would have been abandoned
KN
2
HN
0
PA
mọi người giải giúp em bài này với ạ em đang cần gấp ạ
1
26 tháng 9 2021
a) \(\dfrac{A}{x-2}=\dfrac{x^2+3x+2}{x^2-4}\)
\(\Leftrightarrow\dfrac{A}{x-2}=\dfrac{\left(x+2\right)\left(x+1\right)}{\left(x-2\right)\left(x+2\right)}\)
\(\Leftrightarrow\dfrac{A}{x-2}=\dfrac{x+1}{x-2}\Leftrightarrow A=x+1\)
b) \(\dfrac{M}{x-1}=\dfrac{x^2+3x+2}{x+1}\)
\(\Leftrightarrow\dfrac{M}{x-1}=\dfrac{\left(x+1\right)\left(x+2\right)}{x+1}\)
\(\Leftrightarrow\dfrac{M}{x-1}=x+2\Leftrightarrow M=\left(x-1\right)\left(x+2\right)=x^2+x-2\)
KY
4 tháng 8 2021
asked how much that computer was
wanted to know if I had the keys
asked Sam why he hadn't come to the party
asked Jane where she was going for her holidays
asked me if I spoke English
asked how old her mother was
asked me whether I was British or American
DT
Đỗ Thanh Hải
CTVVIP
4 tháng 8 2021
1 Tom asked how much that computer was
2 The officer wanted to know if I had wanted the key
3 Ann asked Sam why he hadn't come to her party
4 He asked Jane where she was going for her holiday
5 He asked me if I spoke E
6 He asked how old her mother was
7 He asked me whether I was British or American
RH
2 tháng 1 2022
a) x(x + 4) - 3x - 12 = 0
x(x + 4) - 3(x + 4) = 0
(x + 4)(x - 3) = 0
x = -4 hoặc x = 3
b) 2x(x - 4) - x + 4 = 0
2x(x - 4) - (x - 4) = 0
(x - 4)(2x - 1) = 0
x = 4 hoặc x = 1/2
c) 5x(x - 3) - x + 3 = 0
5x(x - 3) - (x - 3) = 0
(x - 3)(5x - 1) = 0
x = 3 hoặc x = 1/5.
2 tháng 1 2022
a) x(x + 4) - 3x - 12 = 0
x(x + 4) - 3(x + 4) = 0
(x + 4)(x - 3) = 0
x = -4 hoặc x = 3
b) 2x(x - 4) - x + 4 = 0
2x(x - 4) - (x - 4) = 0
(x - 4)(2x - 1) = 0
x = 4 hoặc x = 1/2
c) 5x(x - 3) - x + 3 = 0
5x(x - 3) - (x - 3) = 0
(x - 3)(5x - 1) = 0
x = 3 hoặc x = 1/5.
a: \(\left(2x-1\right)^3-4x^2\left(2x-3\right)=5\)
=>\(8x^3-12x^2+6x-1-8x^3+12x^2=5\)
=>6x-1=5
=>6x=6
=>x=1
b: \(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-10\)
=>\(x^3+3x^2+3x+1-\left(x^3-3x^2+3x-1\right)-6\left(x^2-2x+1\right)=-10\)
=>\(x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6=-10\)
=>12x-4=-10
=>12x=-6
=>\(x=-\frac{6}{12}=-\frac12\)
c: \(\left(x+2\right)^3-x^2\left(x+6\right)=4\)
=>\(x^3+6x^2+12x+8-x^3-6x^2=4\)
=>12x+8=4
=>12x=-4
=>\(x=-\frac{4}{12}=-\frac13\)
d: \(\left(x-2\right)^3-x\left(x+1\right)\left(x-1\right)+6x^2=5\)
=>\(x^3-6x^2+12x-8-x\left(x^2-1\right)+6x^2=5\)
=>\(x^3+12x-8-x^3+x=5\)
=>13x-8=5
=>13x=13
=>x=1
e: \(\left(x-1\right)^3+3\left(x+1\right)^2=\left(x+2\right)\left(x^2-2x+4\right)\)
=>\(x^3-3x^2+3x-1+3\left(x^2+2x+1\right)=x^3+8\)
=>\(-3x^2+3x-1+3x^2+6x+3=8\)
=>9x+2=8
=>9x=6
=>\(x=\frac69=\frac23\)
f: \(\left(x-2\right)^3-\left(x-2\right)\left(x^2+2x+4\right)+6\left(x-2\right)\left(x+2\right)=60\)
=>\(x^3-6x^2+12x-8-\left(x^3-8\right)+6\left(x^2-4\right)=60\)
=>\(-6x^2+12x+6x^2-24=60\)
=>12x-24=60
=>12x=84
=>x=7