x/20+x/30+x/42=3
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9 tháng 12 2021
\(2,\)
\(a,20-\left[4^2+\left(x-6\right)\right]=90\)
\(\Rightarrow20-16-x+6=90\)
\(\Rightarrow10-x=90\)
\(\Rightarrow x=-80\)
Vậy: \(x=-80\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2^x-6\right)\right]=3^2+4^2\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2^x-6\right)=25\)
\(\Rightarrow24+2^x=40\)
\(\Rightarrow2^x=16\)
\(\Rightarrow x=4\)
Vậy: \(x=4\)
8 tháng 12 2021
\(2,\)
\(a,20-\left[42+\left(x-6\right)\right]=90\)
\(\Rightarrow20-42-x+6-90=0\)
\(\Rightarrow x=-106\)
Vậy: \(x=-106\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2x-6\right)\right]=32+42\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2x-6\right)=74\)
\(\Rightarrow1000:\left(24+2x\right)=74\)
\(\Rightarrow24+2x=\dfrac{500}{37}\)
\(\Rightarrow2x=-\dfrac{388}{37}\)
\(\Rightarrow x=-\dfrac{194}{37}\)
Mà \(x\in N\)
\(\Rightarrow x\in\varnothing\)
Vậy: \(x\in\varnothing\)
CM
25 tháng 1 2019
a) 12 : x = 3
X = 12 : 3
X = 4
b) 21 : x = 7
X = 21 : 7
X = 3
c) 30 : x = 3
X = 30 : 3
X = 10
d) X : 7 = 4
X = 4 x 7
X = 28
e) 20 : x = 5
X = 20 : 5
X = 4
f) X x 6 = 42
X = 42 : 6
X = 7
LT
1
ND
0
FT
29 tháng 6 2017
( x-2) .3 =18 135-3(x+1)=30
(x-2) =18:3 3(x+1)=135-30
(x-2) =6 3(x+1)=105
x =6+2 x+1 =105:3
x =8 x+1 =35
x =35-1
x =34
(123-x)-72=28 (158-x):7=28
(123-x) =28+72 (158-x) =28.7
(123-x) =100 (158-x) =784
x =123-100 x =158-784
x =23 x =-626
42.x=39.42-37.42
42.x=42.(39-37)
42.x=42.2
x=42.2:42
x =2
bài này dài lắm đó k mik nha
TQ
2
NC
23 tháng 8 2020
Ghi rõ đề ra, VP là bao nhiêu?
Biến đổi VT:
\(x+\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+\frac{x}{30}+\frac{x}{42}+\frac{x}{56}\)
\(=x\left(1+\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}+\frac{1}{7.8}\right)\)
\(=x\left(1+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)
\(=x\left(2-\frac{1}{8}\right)\)
\(=x.\frac{15}{8}\)
KN
23 tháng 8 2020
\(x+\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+\frac{x}{30}+\frac{x}{42}+\frac{x}{56}=28\)
\(\Leftrightarrow x\left(1+\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\right)=28\)
\(\Leftrightarrow x\left(1+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{7}-\frac{1}{8}\right)=28\)
\(\Leftrightarrow x\left(1+1-\frac{1}{8}\right)=28\)
\(\Leftrightarrow x.\frac{15}{8}=28\)
\(\Leftrightarrow x=\frac{224}{15}\)
TM
0
Ta có: \(\frac{x}{20}+\frac{x}{30}+\frac{x}{42}=3\)
=>\(x\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)=3\)
=>\(x\left(\frac14-\frac15+\frac15-\frac16+\frac16-\frac17\right)=3\)
=>\(x\left(\frac14-\frac17\right)=3\)
=>\(x\cdot\frac{3}{21}=3\)
=>\(x=3:\frac{3}{21}=21\)
\(\frac{x}{20}+\frac{x}{30}+\frac{x}{42}=\) \(3\)
\(\frac{21x}{420}+\frac{14x}{420}+\frac{10x}{420}=3\)
\(\frac{45x}{420}=3\)
\(45x=3\times420\)
\(45x=1260\)
\(x=1260:45\)
\(x=28\)