\(\) (1\2-x):1và1/3+1\2=-4
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NK
2
5 tháng 7 2019
\(\frac{2}{3}\cdot x-\frac{1}{4}\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\cdot\frac{2}{3}\)
\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\cdot\frac{2}{3}\)
\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\cdot\frac{7}{12}=\frac{1}{6}\)
\(\Rightarrow\frac{2}{3}.x-\frac{7}{48}=\frac{1}{6}\)
\(\Rightarrow\frac{2}{3}x=\frac{5}{16}\)
\(\Rightarrow x=\frac{15}{32}\)
5 tháng 7 2019
\(\frac{2}{3}\times x-\frac{1}{4}:\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\times\frac{2}{3}\)
\(\frac{2}{3}\times x-\frac{1}{4}:\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\times\frac{2}{3}\)
\(\frac{2}{3}\times x-\frac{1}{4}:\frac{7}{12}=\frac{1}{6}\)
\(\frac{2}{3}\times x-\frac{3}{7}=\frac{1}{6}\)
\(\frac{2}{3}\times x=\frac{1}{6}+\frac{3}{7}\)
\(\frac{2}{3}\times x=\frac{25}{42}\)
\(x=\frac{25}{42}:\frac{2}{3}\)
\(x=\frac{25}{28}\)
25 tháng 6 2023
4:
a: =4/15-2,9+11/15=1-2,9=-1,9
b: \(=-36,75+3,7-63,25+6,3=10-100=-90\)
c: \(=6,5+3,5-\dfrac{10}{17}-\dfrac{7}{17}=10-1=9\)
d: \(=\dfrac{13}{25}\left(-39,1-60,9\right)=\dfrac{13}{25}\left(-100\right)=-52\)
e: =-5/12-7/12-3,7-6,3=-1-10=-11
f: =2,8(-6/13-7/13)-7,2=-2,8-7,2=-10
25 tháng 6 2023
`@` `\text {Ans}`
`\downarrow`
`a.`
`A=(1/2-7/13-1/3)+(-6/13+1/2+1 1/3)`
`= 1/2 - 7/13 - 1/3 - 6/13 + 1/2 + 1 1/3`
`= (1/2 + 1/2) + (-7/13 - 6/13) + (-1/3 + 1 1/3) `
`= 1 - 1 + 1`
`= 1`
`b.`
`B=0,75+2/5+(1/9-1 1/2+5/4)`
`= 3/4 + 2/5 + 1/9 - 3/2 + 5/4`
`= (3/4+5/4)+ 1/9 + 2/5 - 3/2`
`= 2 + 1/9 - 11/10`
`= 19/9 - 11/10`
`= 91/90`
`c.`
`(-5/9).3/11+(-13/18).3/11`
`= 3/11*[(-5/9) + (-13/18)]`
`= 3/11*(-23/18)`
`= -23/66`
`d.`
`(-2/3).3/11+(-16/9).3/11`
`= 3/11* [(-2/3) + (-16/9)]`
`= 3/11*(-22/9)`
`= -2/3`
`e.`
`(-1/4).(-2/13)-7/24.(-2/13)`
`= (-2/13)*(-1/4-7/24)`
`= (-2/13)*(-13/24)`
`= 1/12`
`f.`
`(-1/27).3/7+(5/9).(-3/7)`
`= 3/7*(-1/27 - 5/9)`
`= 3/7*(-16/27)`
`= -16/63`
`g.`
`(-1/5+3/7):2/11+(-4/5+4/7):2/11`
`=[(-1/5+3/7)+(-4/5+4/7)] \div 2/11`
`= (-1/5+3/7 - 4/5 + 4/7) \div 2/11`
`= [(-1/5-4/5)+(3/7+4/7)] \div 2/11`
`= (-1+1) \div 2/11`
`= 0 \div 2/11 = 0`
NT
1
17 tháng 10 2021
A=(6 : 35−116 x 67) : (415 x 1011+5211)A=(6 : 35−116 x 67) : (415 x 1011+5211)
A=(6 : 35−76 x 67) : (215 x 1011+5711)A=(6 : 35−76 x 67) : (215 x 1011+5711)
A=(10−1) : (4211+5711)A=(10−1) : (4211+5711)
A=9 : 9A=9 : 9
A=1
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
5 tháng 8 2023
{\(\dfrac{5}{3}\) - (- \(\dfrac{1}{4}\)): 1\(\dfrac{1}{5}\)} \(\times\) ( \(\dfrac{5}{8}\) + \(\dfrac{9}{4}\))
= { \(\dfrac{5}{3}\) + \(\dfrac{1}{4}\): \(\dfrac{6}{5}\)} \(\times\) \(\dfrac{23}{8}\)
= {\(\dfrac{5}{3}\) + \(\dfrac{5}{24}\)} \(\times\) \(\dfrac{23}{8}\)
= (\(\dfrac{40}{24}\) + \(\dfrac{5}{24}\)) \(\times\) \(\dfrac{23}{8}\)
= \(\dfrac{15}{8}\) \(\times\) \(\dfrac{23}{8}\)
= \(\dfrac{345}{64}\)
PB
4
13 tháng 8 2020
720:[41-(2×x-5)]=120
[41-(2×x-5)]=720:120
[41-(2×x-5)]=6
(2×x-5)=41-6
(2×x-5)=35
2×x=35+5
2x=40
x=40:2
vậy x=20
13 tháng 8 2020
a) \(720:\left[41-\left(2x-5\right)\right]=120\)
\(\Rightarrow\left[41-\left(2.x-5\right)\right]=6\)
\(\Rightarrow2x-5=35\Rightarrow2x=40\Rightarrow x=20\)
b) \(4,8.5-x+100=250\)
\(\Rightarrow4,8.5-x=150\Rightarrow24-x=150\Rightarrow x=-126\)
c)+) \(\frac{3}{5}+\frac{2}{5}:x=1\Rightarrow\frac{2}{5}:x=\frac{2}{5}\Rightarrow x=1\)
+) \(\frac{3}{5}+\frac{2}{5}:x=\frac{1}{4}\Rightarrow\frac{2}{5}:x=\frac{-7}{20}\Rightarrow x=\frac{-8}{7}\)
Cậu có thể tham khảo bài làm trên đây ạ, chúc cậu hok tốt ^^
3 tháng 9 2019
b)0,5x+2/3x+2/3=7/2
1/2x+2/3x+2/3=7/2
x(1/2+2/3)+2/3=7/12
x.7/6+2/3 =7/12
x.7/6 =7/12-2/3
x.7/6 =-1/12
x =-1/12:7/6
x =-1/14
b)3/5-2/15:x=1/2
2/15:x =3/5-1/2
2/15:x =1/10
x =2/15:1/10
x = 4/3
(1/2-x):1 và 1/3+1/2=-4
=>(1/2-x):4/3+1/2=-4
=>(1/2-x):4/3=-4-1/2
=>(1/2-x):4/3=-9/2
=>(1/2-x)=(-9/2) *4/3
=>(1/2-x)=-6
=>x=1/2-(-6)
=>x=13/2
Vậy x=13/2
\(\left(\frac12-x\right):1\frac13+\frac12=-4\)
\(\left(\frac12-x\right):\frac43+\frac12=-\frac82\)
\(\left(\frac12-x\right):\frac43=-\frac82-\frac12\)
\(\left(\frac12-x\right):\frac43=-\frac92\)
\(\frac12-x=-\frac92\cdot\frac43\)
\(\frac12-x=-6\)
\(\frac12-x=-\frac{12}{2}\)
\(x=\frac12-\left(-\frac{12}{2}\right)\)
\(x=\frac12+\frac{12}{2}\)
\(x=\frac{13}{2}\)
Vậy \(x=\frac{13}{2}\)