5/2+5/6+5/18+5/54+5/162
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Đặt tổng trên là A
\(3xA=\dfrac{15}{2}+\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}\)
\(2xA=3xA-A=\dfrac{15}{2}-\dfrac{5}{468}\)
Từ đó suy ra A

C=5/2+5/6+5/18+5/54+5/162+5/486
C=1215/486+405/486+135/486+45/486+15/486+5/486
C=1215+405+135+45+15+5/486
C=1820/486=910/243




Gọi giá trị của biểu thức trên là A. Ta có:
\(A=\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}\)
\(3A=\dfrac{15}{2}+\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}\)
\(3A-A=\left(\dfrac{15}{2}+\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}\right)-\left(\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}\right)\)
\(2A=\dfrac{15}{2}-\dfrac{5}{162}\)
\(A=\left(\dfrac{15}{2}-\dfrac{5}{162}\right)\div2=\dfrac{605}{81}\div2=\dfrac{605}{162}\)
= 10/3 + 5/18 + 5/54 + 5/162
= 65/18 + 5/54 + 5/162
= 100/27 + 5/162
= 605/162

\(\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{18}+\dfrac{5}{54}+\dfrac{5}{162}+\dfrac{5}{486}\)
\(=\dfrac{5.243}{486}+\dfrac{5.81}{486}+\dfrac{5.27}{486}+\dfrac{5.9}{486}+\dfrac{5.3}{486}+\dfrac{5}{486}\)
\(=\dfrac{1215+405+135+45+15+5}{486}\)
\(=\dfrac{1820}{486}=\dfrac{910}{243}\)

Ta có : \(A=\frac{5}{2}+\frac{5}{6}+\frac{5}{18}+\frac{5}{54}+\frac{5}{162}+\frac{5}{468}\)
\(\Leftrightarrow\frac{1}{3}A=\frac{5}{6}+\frac{5}{18}+\frac{5}{54}+\frac{5}{162}+\frac{5}{468}+\frac{5}{1458}\)
\(\Leftrightarrow A-\frac{1}{3}A=\frac{5}{2}-\frac{5}{1458}\)
\(\Leftrightarrow\frac{2}{3}A=\frac{5}{2}-\frac{5}{1458}\)
\(\Leftrightarrow\frac{2}{3}A=\frac{1820}{729}\)
\(\Leftrightarrow A=\frac{1820}{729}.\frac{3}{2}=\frac{910}{243}\)

Đặt \(A=\frac52+\frac56+\frac{5}{18}+\frac{5}{54}+\frac{5}{162}\)
\(3A=\frac{15}{2}+\frac52+\frac56+\frac{5}{18}+\frac{5}{54}\)
\(3A-A=\left(\frac{15}{2}+\frac52+\frac56+\frac{5}{18}+\frac{5}{54}\right)-\left(\frac52+\frac56+\frac{5}{18}+\frac{5}{54}+\frac{5}{162}\right)\)
\(2A=\frac{15}{2}-\frac{5}{162}=\frac{605}{81}\)
\(\Rightarrow A=\frac{605}{81}:2=\frac{605}{162}\)
Đặt tổng trên là A
\(3A=\) \(3\times\left(\frac52+\frac56+\frac{5}{18}+\frac{5}{54}+\frac{5}{162}\right)\)
\(3A=\frac{15}{2}\) \(+\frac56+\) \(\frac{5}{18}+\frac{5}{54}\)
\(3A-A=\) \(\frac{15}{2}\) \(+\frac56+\frac{5}{18}+\frac{5}{54}\) \(-\frac52-\frac56-\frac{5}{18}-\frac{5}{54}-\frac{5}{162}\)
\(2A=\frac52-\frac{5}{162}\)
\(2A=\frac{200}{81}\)
\(A=\frac{200}{81}:2\)
\(A=\frac{100}{81}\)