13/8 : 7 =
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a.11/7.8/13+8/13.3/7+8/13
=8/13.(11/7+3/7+1)
=8/13.3
=24/13
b.5/7.8/13+8/13.9/7-8/13
=8/13.(5/7+9/7-1)
=8/13.1
=8/13
c.157.199-56.199-199
=199.(157-56-1)
=199.100
19900

Bn thấy cái nào cùng mẫu hoặc dễ quy đồng thì nhóm vào 1 nhóm nha!
Xin đừng ném đá, mk chỉ nói đúng
Hội con 🐄 chúc bạn học tốt!!!

\(\dfrac{\dfrac{7}{13}+\dfrac{7}{14}-\dfrac{7}{15}}{\dfrac{8}{13}+\dfrac{8}{14}-\dfrac{8}{15}}-\dfrac{\dfrac{5}{11}-\dfrac{5}{13}+\dfrac{5}{15}}{\dfrac{8}{11}-\dfrac{8}{13}+\dfrac{8}{15}}\)
\(=\dfrac{7\left(\dfrac{1}{13}+\dfrac{1}{14}-\dfrac{1}{15}\right)}{8\left(\dfrac{1}{13}+\dfrac{1}{14}-\dfrac{1}{15}\right)}-\dfrac{5\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{15}\right)}{8\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{15}\right)}\)
\(=\dfrac{7}{8}-\dfrac{5}{8}\)
\(=\dfrac{2}{8}=\dfrac{1}{4}\)

\(\dfrac{4}{7}+\dfrac{46}{13}+\dfrac{25}{8}+\dfrac{3}{7}-\dfrac{1}{8}-\dfrac{7}{13}\)
\(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{46}{13}-\dfrac{7}{13}\right)+\left(\dfrac{25}{8}-\dfrac{1}{8}\right)\)
\(=1+3+3=7\)

\(\dfrac{8}{13}-\dfrac{7}{29}-\dfrac{8}{13}+\dfrac{7}{29}+\dfrac{2019}{2020}=\left(\dfrac{8}{13}-\dfrac{8}{13}\right)-\left(\dfrac{7}{29}+\dfrac{7}{29}\right)+\dfrac{2019}{2020}=0-0+\dfrac{2019}{2020}=\dfrac{2019}{2020}\)


\(\dfrac{1}{7}-\left(-\dfrac{3}{5}\right)+\dfrac{6}{7}-\left|-\dfrac{1}{5}\right|=1+\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{9}{5}\\ \dfrac{8}{13}\cdot\dfrac{11}{18}+\dfrac{7}{18}\cdot\dfrac{8}{13}-1\dfrac{8}{13}=\dfrac{8}{13}\left(\dfrac{11}{18}+\dfrac{7}{18}+1\right)=\dfrac{8}{13}\cdot2=\dfrac{16}{13}\)
\(\dfrac{1}{7}-\left(-\dfrac{3}{5}\right)+\dfrac{6}{7}-\left|-\dfrac{1}{5}\right|\)
\(=\dfrac{1}{7}+\dfrac{3}{5}+\dfrac{6}{7}-\dfrac{1}{5}\)
\(=1+\dfrac{2}{5}=\dfrac{7}{5}\)

a, \(\frac{-3}{7}+\frac{5}{13}-\frac{4}{7}+\frac{8}{13}\)
\(=\frac{-3}{7}-\frac{4}{7}+\frac{5}{13}+\frac{8}{13}\)
\(=-\frac{7}{7}+\frac{13}{13}=-1+1=0\)
b, \(\frac{-5}{14}-\frac{2}{-14}+\frac{1}{8}+\frac{1}{8}\)
\(=\frac{-5}{14}+\frac{2}{14}+\frac{1}{8}+\frac{1}{8}\)
\(=-\frac{3}{14}+\frac{1}{4}=\frac{1}{28}\)
c,\(-\frac{5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\)
\(=-\frac{5}{13}-\frac{3}{13}-\frac{3}{5}+\frac{4}{10}\)
\(=-\frac{8}{13}-\frac{3}{5}+\frac{4}{10}=-\frac{79}{65}+\frac{4}{10}=-\frac{53}{65}\)
d, \(\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{4}{6}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)
\(=\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{2}{3}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)
\(=\left[\left(\frac{1}{8}-\frac{1}{2}-\frac{9}{7}-\frac{12}{7}+\frac{2}{3}\right)+\frac{5}{9}\right]\)
\(=-\frac{65}{24}+\frac{5}{9}=-2\frac{11}{72}\)
a)-3/7+5/13-4/7+8/13
=-3/7-4/7+5/13+8/13
=-7/7+13/13
=-1+1
=0

\(\frac{\frac{7}{9}-\frac{7}{13}-\frac{7}{15}-\frac{7}{8}}{\frac{5}{9}-\frac{5}{13}-\frac{5}{15}-\frac{5}{8}}=\frac{7.\left(\frac{1}{9}-\frac{1}{13}-\frac{1}{15}-\frac{1}{8}\right)}{5.\left(\frac{1}{9}-\frac{1}{13}-\frac{1}{15}-\frac{1}{8}\right)}=\frac{7}{5}\)
13/56
\(\dfrac{13}{8}:7=\dfrac{13}{8\times7}=\dfrac{13}{56}\)