\(\left(\frac{11}{3}x+\frac73\right):2=-\frac23\)
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Khách
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HQ
Hà Quang Minh
Giáo viên
19 tháng 9 2023
a)
\(\begin{array}{l}x:{\left( {\frac{{ - 1}}{2}} \right)^3} = - \frac{1}{2}\\x = - \frac{1}{2}.{\left( {\frac{{ - 1}}{2}} \right)^3}\\x = {\left( {\frac{{ - 1}}{2}} \right)^4}\\x = \frac{1}{{16}}\end{array}\)
Vậy \(x = \frac{1}{{16}}\).
b)
\(\begin{array}{l}x.{\left( {\frac{3}{5}} \right)^7} = {\left( {\frac{3}{5}} \right)^9}\\x = {\left( {\frac{3}{5}} \right)^9}:{\left( {\frac{3}{5}} \right)^7}\\x = {\left( {\frac{3}{5}} \right)^2}\\x = \frac{9}{{25}}\end{array}\)
Vậy \(x = \frac{9}{{25}}\).
c)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^{11}}:x = {\left( {\frac{{ - 2}}{3}} \right)^9}\\x = {\left( {\frac{{ - 2}}{3}} \right)^{11}}:{\left( {\frac{{ - 2}}{3}} \right)^9}\\x = {\left( {\frac{{ - 2}}{3}} \right)^2}\\x = \frac{4}{9}.\end{array}\)
Vậy \(x = \frac{4}{9}\).
d)
\(\begin{array}{l}x.{\left( {0,25} \right)^6} = {\left( {\frac{1}{4}} \right)^8}\\x.{\left( {\frac{1}{4}} \right)^6} = {\left( {\frac{1}{4}} \right)^8}\\x = {\left( {\frac{1}{4}} \right)^8}:{\left( {\frac{1}{4}} \right)^6}\\x = {\left( {\frac{1}{4}} \right)^2}\\x = \frac{1}{{16}}\end{array}\)
Vậy \(x = \frac{1}{{16}}\).
4 tháng 7 2017
a) 3. ( x - 2/5 ) = 0
<=> x = 0 : 3 + 2/5
<=> x = 2/5
( Theo cách lớp 6)
Hoặc cách thông thường nek:
3. ( x - 2/5 ) = 0
x - 2/5 = 0 : 3
x - 2/5 = 0
x = 0 + 2/5
x = 2/5
Mấy câu sau làm như vậy nha!
^^ Chúc học tốt!!!!
S
9 tháng 3
\(a;x:\left(9\dfrac{1}{2}-\dfrac{3}{2}\right)=\dfrac{\dfrac{2}{5}+\dfrac{4}{9}-\dfrac{5}{11}}{\dfrac{8}{5}+\dfrac{16}{9}-\dfrac{20}{11}}\\ x:8=\dfrac{1}{4}\Rightarrow x=\dfrac{1}{4}\cdot8=2\)
\(b;\left|2x-\dfrac{1}{3}\right|-\left(-2^2\right)=4\left(\dfrac{1}{-2}\right)^3\\ \left|2x-\dfrac{1}{3}\right|+4=-\dfrac{1}{2}\\ \left|2x-\dfrac{1}{3}\right|=-\dfrac{1}{2}-4=-\dfrac{9}{2}\\ \Rightarrow\left[{}\begin{matrix}2x-\dfrac{1}{3}=-\dfrac{9}{2}\Rightarrow x=-\dfrac{25}{12}\\2x-\dfrac{1}{3}=\dfrac{9}{2}\Rightarrow x=\dfrac{29}{12}\end{matrix}\right.\)
5 tháng 6 2015
Vê trái:
\(=\frac{2}{\left(x-1\right)\left(x+1\right)}+\frac{4}{\left(x-2\right)\left(x+2\right)}+...+\frac{20}{\left(x-10\right)\left(x+10\right)}\)
\(=\frac{\left(x+1\right)-\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}+\frac{\left(x+2\right)-\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}+...+\frac{\left(x+10\right)-\left(x-10\right)}{\left(x+10\right)\left(x-10\right)}\)
\(=\frac{1}{x-1}-\frac{1}{x+1}+\frac{1}{x-2}-\frac{1}{x+2}+...+\frac{1}{x-10}-\frac{1}{x+10}\)
\(=\left(\frac{1}{x-1}+\frac{1}{x-2}+...+\frac{1}{x-10}\right)-\left(\frac{1}{x+1}+\frac{1}{x+2}+...+\frac{1}{x+10}\right)\)
Vế phải:
\(=\frac{\left(x+1\right)-\left(x-10\right)}{\left(x-10\right)\left(x+1\right)}+\frac{\left(x+2\right)-\left(x-9\right)}{\left(x-9\right)\left(x+2\right)}+...+\frac{\left(x+10\right)-\left(x-1\right)}{\left(x-1\right)\left(x+10\right)}\)
\(=\frac{1}{x-10}-\frac{1}{x+1}+\frac{1}{x-9}-\frac{1}{x+2}+...+\frac{1}{x-1}-\frac{1}{x+10}\)
\(=\left(\frac{1}{x-1}+\frac{1}{x-2}+...+\frac{1}{x-10}\right)-\left(\frac{1}{x+1}+\frac{1}{x+2}+...+\frac{1}{x+10}\right)\) = vế phải
=> đpcm
KN
5 tháng 3 2020
\(\left(1\right)\Leftrightarrow2x-3x^2+11-33x=6x-4-15x^2+10x\)
\(\Leftrightarrow12x^2-47x+15=0\)
\(\Delta=47^2-4.12.15=1489,\sqrt{\Delta}=\sqrt{1489}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{47+\sqrt{1489}}{24}\\x=\frac{47-\sqrt{1489}}{24}\end{cases}}\)
KN
5 tháng 3 2020
\(\left(2\right)\Leftrightarrow\frac{\left(x-3\right)^2-\left(x+3\right)^2}{x^2-9}=\frac{-5}{x^2-9}\)
\(\Leftrightarrow\left(x-3\right)^2-\left(x+3\right)^2=-5\)
\(\Leftrightarrow x^2-6x+9-x^2-6x-9=-5\)
\(\Leftrightarrow-12x=-5\Leftrightarrow x=\frac{5}{12}\)
\(\frac{11}{3}x+\frac73=-\frac23\times2=-\frac43\)
\(\frac{11}{3}x=-\frac43-\frac73=-\frac{11}{3}\)
\(x=-\frac{11}{3}:\frac{11}{3}=-\frac{11}{3}\times\frac{3}{11}=-1\)