-3 / 13 + -7/17 + -5 / 19 + -10 / 13 + 24/17 + -14/ 19.sos
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HT
2
MN
10 tháng 5 2021
\(-\dfrac{3}{13}-\dfrac{7}{17}+\left(-\dfrac{5}{19}\right)+\left(-\dfrac{10}{13}\right)+\dfrac{24}{17}-\dfrac{4}{19}\)
\(=\left(-\dfrac{3}{13}-\dfrac{10}{13}\right)-\left(\dfrac{7}{17}-\dfrac{24}{17}\right)+\left(-\dfrac{5}{19}-\dfrac{4}{19}\right)\)
\(=-\dfrac{13}{13}-\left(-\dfrac{17}{17}\right)+-\dfrac{9}{19}\)
\(=-1+1+-\dfrac{9}{19}=-\dfrac{9}{19}\)
10 tháng 5 2021
\(\dfrac{-3}{13}-\dfrac{7}{17}+\left(\dfrac{-5}{19}\right)+\left(\dfrac{-10}{13}\right)+\dfrac{24}{17}-\dfrac{4}{19}\)
=\(\left(\dfrac{-3}{13}+\dfrac{-10}{13}\right)+\left(\dfrac{-7}{17}+\dfrac{24}{17}\right)+\left(\dfrac{-5}{19}-\dfrac{4}{19}\right)\)
=-1+1+\(\dfrac{-9}{19}\)
=0+\(\dfrac{-9}{19}\) =\(\dfrac{-9}{19}\)
S
10 tháng 3 2023
\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)
\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)
\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)
14 tháng 4 2023
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
22 tháng 12 2021
1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
22 tháng 12 2021
1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
DT
Đỗ Thanh Hải
CTVVIP
11 tháng 3 2021
a) \(\dfrac{\dfrac{3}{14}-\dfrac{3}{17}+\dfrac{3}{19}}{\dfrac{5}{19}+\dfrac{5}{14}-\dfrac{5}{17}}=\dfrac{3\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}{5\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}=\dfrac{3}{5}\)
DT
Đỗ Thanh Hải
CTVVIP
11 tháng 3 2021
c) \(\dfrac{\dfrac{2}{7}+\dfrac{2}{5}+\dfrac{2}{17}-\dfrac{2}{193}}{\dfrac{3}{7}+\dfrac{3}{5}+\dfrac{3}{17}-\dfrac{3}{293}}=\dfrac{2\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}{3\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}=\dfrac{2}{3}\)
d)
−133−177−195−1310+1724−1917 \(= \left(\right. - \frac{3}{13} - \frac{10}{13} \left.\right) + \left(\right. - \frac{7}{17} + \frac{24}{17} \left.\right) + \left(\right. - \frac{5}{19} - \frac{17}{19} \left.\right)\) \(= - \frac{13}{13} + \frac{17}{17} - \frac{22}{19}\) \(= - 1 + 1 - \frac{22}{19}\) \(= - \frac{22}{19}\)
\(\left(-\dfrac{3}{13}\right)+\left(-\dfrac{7}{17}\right)+\left(-\dfrac{5}{19}\right)+\left(-\dfrac{10}{13}\right)+\dfrac{24}{17}+\left(-\dfrac{14}{19}\right)\\ =\left[\left(-\dfrac{3}{13}\right)+\left(-\dfrac{10}{13}\right)\right]+\left[\left(-\dfrac{7}{17}\right)+\dfrac{24}{17}\right]+\left[\left(-\dfrac{5}{19}\right)+\left(-\dfrac{14}{19}\right)\right]\\ =\left(-1\right)+1+\left(-1\right)=-1\)