Giúp mình với, mình đang cần gấp:
a,4/5+(-1)/9-7/3 ;b,-2/19+8/13-17/19+1 và 3/4+-5/-13; c,9/7-2/7:0,25+2/3; d,4/13*5/11+4/13*6/11-4/13; e,10/17+-5/13+7/17-8/13
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\(7\frac{5}{9}-\left(3\frac{5}{9}-2\frac{3}{4}\right)=7\frac{5}{9}-3\frac{5}{9}+2\frac{3}{4}=4+2\frac{3}{4}=6\frac{3}{4}\)
\(7\frac{5}{9}-\left(3\frac{5}{9}-2\frac{3}{4}\right)=7\frac{5}{9}-3\frac{5}{9}+2\frac{3}{4}=4+2\frac{3}{4}=6\frac{3}{4}\)
`a, 3/4 + 1/2 xx 7/2`
`= 3/4 + 7/4`
`=10/4`
`=5/2`
`b, 6/15 - 1/3 : 5/3`
`= 6/15 - 1/3 xx 3/5`
`= 6/15 - 3/15`
`= 3/15`
`=1/5`
`c, x-4/9 = 3/7 : 9/4`
`=> x-4/9= 3/7 xx 4/9`
`=> x-4/9= 12/63`
`=> x-4/9=4/21`
`=> x= 4/21 +4/9`
`=>x= 40/63`
`d, 7/9 xx 3/5 -1/2=1/5`
`->` sao lại bằng có `x` ko vậy ạ?
`a,`
`3/4+1/2 \times 7/2=3/4+7/4=10/4=5/2`
`b,`
`6/15 - 1/3 \div 5/3=6/15-1/5=1/5`
`c,` Tìm x?
`x-4/9=3/7 \div 9/4`
`x-4/9=4/21`
`x=4/21+4/9`
`x=40/63`
`d, 7/9x \times 3/5-1/2=1/5`
`7/9x \times 3/5=1/5+1/2`
`7/9x \times 3/5=7/10`
`7/9x=7/10 \div 3/5`
`7/9x=7/6`
`x=7/6 \div 7/9=3/2`
\(A=\frac{-7}{21}+\left(1+\frac{1}{3}\right)\)
\(A=\frac{-7}{21}+1+\frac{1}{3}\)
\(A=\left(\frac{-7}{21}+\frac{1}{3}\right)+1\)
\(A=0+1\\ A=1\)
\(B=\frac{2}{15}+\left(\frac{5}{9}+-\frac{6}{9}\right)\)
\(B=\frac{2}{15}+\frac{-1}{9}\)
\(B=\frac{1}{45}\)
\(C=\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(C=\frac{-1}{5}+\left(\frac{3}{12}+\frac{-3}{4}\right)\)
\(C=\frac{-1}{5}+\frac{-1}{2}\)
\(C=\frac{-7}{10}\)
\(A=\frac{-7}{21}+\left(1+\frac{1}{3}\right)\)
\(A=\frac{-1}{3}+1+\frac{1}{3}\)
\(A=1\)
\(B=\frac{2}{15}+\left(\frac{5}{9}+\frac{-6}{9}\right)\)
\(B=\frac{2}{15}+\frac{5}{9}+\frac{-6}{9}\)
\(B=\frac{2}{15}+\frac{5}{9}+\frac{-10}{15}\)
\(B=\frac{-8}{15}+\frac{5}{9}\)
\(B=\frac{1}{45}\)
\(C=\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(C=\frac{-1}{5}+\frac{3}{4}+\frac{-3}{4}\)
\(C=\frac{-1}{5}\)
\(=\dfrac{2}{3}+\dfrac{1}{3}.\left(\dfrac{7}{18}\right):\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{7}{54}:\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{2}{9}\)
\(=\dfrac{8}{9}\)
a)\(\frac{3}{7}\times\frac{1}{3}+\frac{10}{7}=\frac{1}{7}+\frac{10}{7}=\frac{11}{7}\)
b)\(\frac{9}{5}-\left(\frac{27}{36}-\frac{4}{36}\right)=\frac{9}{5}-\frac{23}{36}=\frac{324}{180}-\frac{115}{180}=\frac{209}{180}\)
a)3/7: 3+5x2/7
=1/7+10/7
=11/7
b)9/5-(3/4-1/9)
=9/5-23/36
=209/180
a: \(\dfrac{4}{5}+\dfrac{-1}{9}-\dfrac{7}{3}=\dfrac{4}{5}-\dfrac{1}{9}-\dfrac{21}{9}=\dfrac{4}{5}-\dfrac{20}{9}\)
\(=\dfrac{36}{45}-\dfrac{100}{45}=-\dfrac{64}{45}\)
b: \(-\dfrac{2}{19}+\dfrac{8}{13}-\dfrac{17}{19}+1\dfrac{3}{4}+\dfrac{-5}{-13}\)
\(=\left(-\dfrac{2}{19}-\dfrac{17}{19}\right)+\left(\dfrac{8}{13}+\dfrac{5}{13}\right)+\dfrac{7}{4}\)
\(=-\dfrac{19}{19}+\dfrac{13}{13}+\dfrac{7}{4}=\dfrac{7}{4}\)
c: \(\dfrac{9}{7}-\dfrac{2}{7}:0,25+\dfrac{2}{3}\)
\(=\dfrac{9}{7}-\dfrac{2}{7}:\dfrac{1}{4}+\dfrac{2}{3}=\dfrac{9}{7}-\dfrac{8}{7}+\dfrac{2}{3}\)
\(=\dfrac{1}{7}+\dfrac{2}{3}=\dfrac{3}{21}+\dfrac{14}{21}=\dfrac{17}{21}\)
d: \(\dfrac{4}{13}\cdot\dfrac{5}{11}+\dfrac{4}{13}\cdot\dfrac{6}{11}-\dfrac{4}{13}\)
\(=\dfrac{4}{13}\left(\dfrac{5}{11}+\dfrac{6}{11}-1\right)\)
\(=\dfrac{4}{13}\left(\dfrac{11}{11}-1\right)=\dfrac{4}{13}\cdot0=0\)
e: \(\dfrac{10}{17}+\dfrac{-5}{13}+\dfrac{7}{17}-\dfrac{8}{13}\)
\(=\left(\dfrac{10}{17}+\dfrac{7}{17}\right)-\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{17}{17}-\dfrac{13}{13}=1-1=0\)