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sửa lỗi:

1-3=4 --> 1+3=4

2-2=4 --> 2+2=4

a: \(C=\dfrac{-1}{2}:\dfrac{-2}{3}:\dfrac{-3}{4}\)

\(=\dfrac{-1}{2}\cdot\dfrac{3}{-2}\cdot\dfrac{4}{-3}\)

\(=-\dfrac{4}{4}=-1\)

b: \(D=\dfrac{-6}{5}:\dfrac{-5}{4}:\dfrac{-4}{3}\)

\(=-\dfrac{6}{5}\cdot\dfrac{4}{5}\cdot\dfrac{3}{4}\)

\(=\dfrac{-18}{25}\)

c: \(\dfrac{4}{20}+\dfrac{16}{42}+\dfrac{6}{15}+\dfrac{-3}{5}+\dfrac{2}{21}+\dfrac{-10}{21}+\dfrac{3}{20}\)

\(=\left(\dfrac{4}{20}+\dfrac{-3}{5}+\dfrac{6}{15}\right)+\left(\dfrac{16}{42}+\dfrac{2}{21}-\dfrac{10}{21}\right)+\dfrac{3}{20}\)

\(=\left(\dfrac{1}{5}-\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{8}{21}+\dfrac{2}{21}-\dfrac{10}{21}\right)+\dfrac{3}{20}\)

\(=\dfrac{3}{20}\)

d: \(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)

\(=\dfrac{21}{23}+\dfrac{125}{93}+\dfrac{-21}{21}+\dfrac{-125}{143}\)

\(=\dfrac{125}{93}-\dfrac{125}{143}=\dfrac{6250}{13299}\)

20 tháng 1 2024

Câu d, chỗ \(\dfrac{-21}{21}\) phải sửa thành \(\dfrac{-21}{23}\)

17 tháng 4 2022

s

S

Đ

17 tháng 4 2022

S

S

Đ?

2/3:3/4=2/3 x 4/3=8/9

2/3:4/5=2/3 x 5/4=10/12=5/6

1/2:3/4=1/2x4/3=2/3

1/6:1/3=1/6 x 3/1=1/2

12 tháng 3 2022

8/9

5/6

2/3

1/2

Bấm máy tín ik nha pp :)))))))))))))))))))))))))

12 tháng 3 2022

8/9 

4/6

10/12

3/6

2 tháng 10 2018

59 – 43 – 8 = 8           

59 – 42 – 3 = 14           

58 – 41 – 9 = 8

59 – 42 – 4 = 13

Đáp án cần chọn là A

a) 2.(x-1)=4/3

<=> (X-1)= 4/3 :2 = 2/3

<=> X= 2/3+1=5/3

b) (x-1)^2= 4

<=> X-1=2 hoặc x-1=-2

<=> X= 3 hoặc x= -1

c) 2.|x+1|=3

<=> Ix+1| = 3/2

<=> X+1= 3/2 hoặc x+1= -3/2

<=> X= 1/2 hoặc x= -5/2

a) Ta có: \(2\left(x-1\right)=\dfrac{4}{3}\)

\(\Leftrightarrow x-1=\dfrac{4}{3}:2=\dfrac{4}{6}=\dfrac{2}{3}\)

hay \(x=\dfrac{5}{3}\)

Vậy: \(x=\dfrac{5}{3}\)

b) Ta có: \(\left(x-1\right)^2=4\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy: \(x\in\left\{3;-1\right\}\)

1 tháng 3 2020

1+40/x=21

40/x=21-1

40/x=20

x=40/20

x=2

19 tháng 7 2019

1+3+4+5+7+9+6+1+5+4+8+10+1+4+4+452+424+2+42+4+2+4

= 1002

(๑→ܫ←)Hanna Maia(❍ᴥ❍ʋ)

24 tháng 2 2019

\(\frac{2}{3}+2+\frac{4}{18}=\frac{2}{3}+2+\frac{2}{9}=\frac{6}{9}+\frac{18}{9}+\frac{2}{9}=\frac{6+18+2}{9}=\frac{26}{9}\)\(\frac{26}{9}\)

\(\frac{4}{3}-\frac{2}{5}+\frac{1}{2}=\frac{40}{30}-\frac{12}{30}+\frac{15}{30}=\frac{40-12+15}{30}=\frac{43}{30}\)

\(\frac{1}{72}+\frac{1}{56}+\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}=\)\(\frac{1}{8}-\frac{1}{9}+\frac{1}{7}-\frac{1}{8}+\frac{1}{6}-\frac{1}{7}+\frac{1}{5}-\frac{1}{6}+\frac{1}{4}-\frac{1}{5}+\frac{1}{3}-\frac{1}{4}=\)\(\frac{1}{3}-\frac{1}{9}=\frac{3}{9}-\frac{1}{9}=\frac{3-1}{9}=\frac{2}{9}\)

1: =1/5-1/4=-1/20

2: =6/8-7/8=-1/8

3: =11/18-14/18=-3/18=-1/6

4: =-28/210+90/210+28/210=3/7

5: =-8/17-34/17=-42/17

11 tháng 2 2022

1)\(\dfrac{1}{5}+\dfrac{-1}{-4}=\dfrac{4}{20}+\dfrac{5}{20}=\dfrac{9}{20}\)

\(\)2)\(\dfrac{3}{4}+\dfrac{-7}{8}=\dfrac{6}{8}+\dfrac{-7}{8}=\dfrac{-1}{8}\)

3)\(\dfrac{11}{18}+\dfrac{-7}{9}=\dfrac{11}{18}+\dfrac{-14}{18}=\dfrac{-3}{18}=\dfrac{-1}{6}\)

4)\(\dfrac{2}{-15}+\dfrac{3}{7}+\dfrac{-4}{-30}=\dfrac{-2}{15}+\dfrac{2}{15}+\dfrac{3}{7}=0+\dfrac{3}{7}=\dfrac{3}{7}\)

5)\(\dfrac{8}{-17}+\left(-2\right)=\dfrac{-8}{17}+\dfrac{-34}{17}=\dfrac{-42}{17}\)