6(nhân) 2 + 3 -1=
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a) \(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}\)
\(=1-\frac{1}{4}\)
\(=\frac{3}{4}\)
b) \(\frac{4}{7}\times\frac{8}{9}+\frac{4}{7}\times\frac{1}{9}\)
\(=\frac{4}{7}\times\left(\frac{8}{9}+\frac{1}{9}\right)\)
\(=\frac{4}{7}\times1\)
\(=\frac{4}{7}\)
c) \(\frac{13}{6}\times\frac{3}{8}-\frac{3}{8}\times\frac{7}{6}\)
\(=\frac{3}{8}\times\left(\frac{13}{6}-\frac{7}{6}\right)\)
\(=\frac{3}{8}\times1\)
\(=\frac{3}{8}\)
d) \(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{9x10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)


\(3\left(x-\dfrac{1}{6}\right)-2\left(x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy \(x=\dfrac{1}{2}\)

6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001

\(a,\dfrac{3}{4}x-\dfrac{2}{3}x=\dfrac{2}{7}\times\dfrac{1}{6}+\dfrac{5}{7}\times\dfrac{1}{6}\)
\(\dfrac{9}{12}x-\dfrac{8}{12}x=\dfrac{1}{6}\times\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\)
\(\dfrac{1}{12}x=\dfrac{1}{6}\)
\(x=\dfrac{1}{6}:\dfrac{1}{12}\)
\(x=\dfrac{1}{6}\times12\)
\(x=2\)

tính bằng cách thuân tiên nhất
(1-1/2) nhân (1-1/3) nhân (1-1/4) nhân (1-1/5) nhân (1-1/6)
14
14