−178 − ( 3× + 1) = ( −3 ) . ( −7 )
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\(19a+\dfrac{7}{a}>\dfrac{178}{3}\)
\(\Leftrightarrow\dfrac{19a^2+7}{a}>\dfrac{178}{3}\)
\(\Leftrightarrow57a^2+21>178a\)
\(\Leftrightarrow57a^2-178a+21>0\)
\(\Leftrightarrow\left(a-3\right)\left(57a-7\right)>0\)
\(\Leftrightarrow a>3\) đúng theo giả thiết
\(\Rightarrowđpcm\)

a) A=\(\frac{178}{179}+\frac{179}{180}+\frac{183}{181}\)
ta có :
\(A=\left(1-\frac{1}{179}\right)+\left(1-\frac{1}{180}\right)+\left(1+\frac{2}{181}\right)\)
\(\Rightarrow A=\left(1+1+1\right)-\left(\frac{1}{179}-\frac{1}{180}+\frac{2}{181}\right)\)
\(\Rightarrow A=3-\left(\frac{1}{179}-\frac{1}{180}+\frac{2}{181}\right)< 3\)
Vậy \(A< 3\)
a. Ta có :
\(\frac{178}{179}< 1\left(\frac{1}{179}\right)\)
\(\frac{179}{180}< 1\left(\frac{1}{180}\right)\)
\(\frac{183}{181}>1\left(\frac{3}{181}\right)\left(1\right)\)
Mà \(\frac{3}{181}>\frac{1}{179}+\frac{1}{180}\left(=\frac{359}{32220}< \frac{3}{181}\right)\left(2\right)\)
Từ \(\left(1\right)\&\left(2\right)\Rightarrow\frac{178}{179}+\frac{179}{180}+\frac{183}{181}< 1+1+1\)
Vậy \(A< 3\)

Nhìn vào đề bài,ta làm tiếp:
=178x(96+3+2-1)
=178x100
=17800
k cho mik nha
178 x 96 + 3 x 178 + 178 x 2 - 178
= 178 x ( 96 + 3 + 2 - 1 )
= 178 x (96 + 5 - 1 )
= 178 x ( 96 + 4 )
= 178 x 100
= 17800

a )531 + ( 218 - x ) = 735
218 - x = 735 - 531
218 - x = 204
x = 218 - 204
x = 14
a ) 541 + ( 218 - x ) = 735
218 - x = 735 - 541
218 - x = 194
x = 218 - 194
x = 24

\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)
\(=3^3\cdot5^3-20\cdot45176978\)
\(=3375-903539560\)
\(=-903536185\)
\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)
\(=626500:\left\{50^2:\left[178-112\right]\right\}\)
\(=626500:\left\{50^2:66\right\}\)
\(=626500:\frac{1250}{33}\)
\(=\frac{82698}{5}\)
CHUC BAN HOC TOT >.<

\(\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{a\left(a+4\right)}\)
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{a}-\frac{1}{a+4}\)
\(=\frac{1}{3}-\frac{1}{a+4}\)

(-5)+12+(-7)+178+(-179)+1+(-319156)=-319156
tick nha Minh

\(3\frac{1}{5}x+125x=178\)
=> 3,2x + 125x = 178
=> 128,2x = 178
\(\Rightarrow x=\frac{890}{641}\)
\(3\frac{1}{5}x+125x=178 \)
\(\frac{16}{5}x+125x=178\)
\(x.\left(\frac{16}{5}+125\right)=178\)
\(x.\frac{641}{5}=178\)
\(x=178:\frac{641}{5}\)
\(x=\frac{890}{641}\)
vậy \(x=\frac{890}{641}\)
\(-178-\left(3x+1\right)=\left(-3\right).\left(-7\right)\)
\(-178-\left(3x+1\right)=21\)
\(3x+1=-178-21\)
\(3x+1=-199\)
\(3x=-199-1\)
\(3x=-200\)
\(x=-200:3\)
\(x=\frac{-200}{3}\)
\(Vậy\) \(x\) \(=\) \(\frac{-200}{3}\)