5 x 8 + 5 x12 + 5x80
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a: -3/4x12=-36/4=-9
b: \(=\dfrac{7}{15}\cdot\dfrac{10}{21}=\dfrac{7}{21}\cdot\dfrac{10}{15}=\dfrac{1}{3}\cdot\dfrac{2}{3}=\dfrac{2}{9}\)
c: \(=\dfrac{7}{18}\cdot\dfrac{12}{21}=\dfrac{12}{18}\cdot\dfrac{7}{21}=\dfrac{2}{3}\cdot\dfrac{1}{3}=\dfrac{2}{9}\)
d: \(=\dfrac{11}{15}\cdot\dfrac{5}{22}=\dfrac{11}{22}\cdot\dfrac{5}{15}=\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}\)
e: \(=-\dfrac{8}{15}\cdot\dfrac{5}{4}=\dfrac{-40}{60}=\dfrac{-2}{3}\)
f: \(=-15\cdot\dfrac{3}{5}=-9\)

c, \(\frac{4.5.6.7.8}{8.10.12.14.16}\)
\(=\frac{4.5.6.7.8}{4.2.5.2.6.2.7.2.8.2}\)
\(=\frac{1}{2.2.2.2.2}\)
\(=\frac{1}{32}\).
=4.5.6.7.8 =1 =1
8.5.2.6.2.7.2.4.4 2.2.2.4 32
chúc bn hok tốt

A = 2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40
= 24 x 53 + 24 x 87 - 24 x 40
= 24 x ( 53 + 87 - 40 )
= 24 x 100
= 2400
B = 5 x 7 x 77 - 7 x 60 + 49 x 25 - 15 x 42
= 5 x 7 x 77 - 7 x 5 x 12 + 49 x 5 x 5 - 5 x 3 x 42
= 5 x 539 - 84 x 5 + 245 x 5 - 5 x 126
= 5 x ( 539 - 84 + 245 - 126 )
= 5 x 574
= 2870
a=2×53×12+4×6×87-3×8×40
a=24×53+24×87-24×40
a=24×(53+87-40)
a=24×100
a=2400


a) 4(-5)=(-2)10
ta có: 4/-2=10/-5
-5/-2=10/4
-5/10=-2/4
-2/4=-5/10
b) (-6)(-8)=4.12
ta có: -6/4=12/-8
-6/12=4/-8
4/-6=-8/12
4/-8=-6/12

dễ quá em ơi nó bằng 5,243,806,989,347.97
Không cần cảm ơn chị nhé chị đang học lớp 5 hi hi

\(12+x+\left(-5\right)=-18\)
\(\Leftrightarrow x=-18-12+5\)
\(\Leftrightarrow x=-25\)
12 + x + ( -5 ) = -18
7 + x = -18
x = -18 - 7
x = -25

` 3/7 + 3/4 - 1/2 = 12/28 + 21/28 - 14/28 = 33/28 - 14/28 = 19/28`
` 6/11 + 2/9 xx 12 = 6/11 + 8/3 = 18/33 + 88/33 = 106/33`
` 5/7 - 8/5 : 4 = 5/7 - 8/5 xx 1/4 = 5/7 - 2/5 = 25/35- 14/35 = 11/35`
\(\dfrac{3}{7}+\dfrac{3}{4}-\dfrac{1}{2}=\dfrac{12}{28}+\dfrac{21}{28}=\dfrac{33}{28}-\dfrac{1}{2}=\dfrac{33}{28}-\dfrac{14}{28}=\dfrac{19}{28}\)
\(\dfrac{6}{11}+\dfrac{2}{9}\times12=\dfrac{54}{99}+\dfrac{22}{99}=\dfrac{76}{99}\times12=\dfrac{76\times12}{99}=\dfrac{912}{99}\)
\(\dfrac{5}{7}-\dfrac{8}{5}:4=\dfrac{5}{7}-\dfrac{8}{4}\times\dfrac{1}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{10}{14}-\dfrac{7}{14}=\dfrac{3}{14}\)

a: \(\text{Δ}=\left[-2\left(m+1\right)\right]^2-4\cdot1\cdot\left(m^2-4m+5\right)\)
\(=4\left(m+1\right)^2-4\left(m^2-4m+5\right)\)
\(=4m^2+8m+4-4m^2+16m-20\)
=24m-16
Để phương trình có hai nghiệm thì Δ>=0
=>24m-16>=0
=>24m>=16
=>\(m>=\dfrac{2}{3}\)
b: Bạn xem lại đề nha bạn
5 x 8 + 5 x12 + 5 x 80 = 5 x (8+12+80) = 5 x100 =500