so sánh : 2^200 và 3^200
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a.
\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}=\left(2^3\right)^{100}=2^{300}\)
Vậy \(3^{200}>2^{300}\)
b.
\(5^{200}=\left(5^2\right)^{100}=25^{100}< 32^{100}=\left(2^5\right)^{100}=2^{500}\)
Vậy \(5^{200}< 2^{500}\)
Ta có : \(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
\(\Rightarrow9^{100}>8^{100}\)
\(\Rightarrow3^{200}>2^{300}\)
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\(2^{200}< 3^{200}vi2< 3\)
chúc bnm học gioi!
nhae@@@
hihikudo shinichi
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\(2^{300}=\left(2^3\right)^{100}=8^{100}< 9^{100}=\left(3^2\right)^{100}=3^{200}\)
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\(2^{300}=\left(2^3\right)^{100}=8^{100}\\ 3^{200}=\left(3^2\right)^{100}=9^{100}\\ Vì:8^{100}< 9^{100}\Rightarrow2^{300}< 3^{200}\)
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\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}\)
\(\Rightarrow2^{300}< 3^{200}\)
`@` `\text {Ans}`
`\downarrow`
Ta có:
\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}\)
Vì `8 < 9 \Rightarrow `\(8^{100}< 9^{100}\)
`\Rightarrow `\(2^{300}< 3^{200}\)
___
`@` So sánh `2` lũy thừa cùng số mũ:
`a^m > b^m` khi `a > b.`
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\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}\)
mà \(8^{100}< 9^{100}\left(8< 9\right)\)
nên \(2^{300}< 3^{200}\)
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ta có :
2300=(23)100=8100
3200=(32)100=9100
vì 8100<9100 nên 2300<3200
\(2^{300}=\left(2^3\right)^{100}\) \(\Rightarrow8^{100}\)
\(3^{200}=\left(3^2\right)^{100}\) \(\Rightarrow9^{100}\)
\(\Rightarrow8^{100}<9^{100}\)\(\Leftrightarrow2^{300}<3^{200}\)
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TC:(1/2)^300=(1/8)^100
(1/3)^200=(1/9)^100
Vì (1/8)^100>(1/9)^100 =>(1/2)^300 >(1/3)^200
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3200 = 32.100 = 9100 (1)
2300 = 23.100 = 8100 (2)
Từ (1) và(2) ta có: 3200>2300
3200 = 32.100 = (32)100 = 9100
2300 = 23.100 = (23)100 = 8100
9100 > 8100 ( vì 9 > 8 ) nên 3200 > 2300.
sos
\(2^{200}< 3^{200}\left(2< 3\right)\)