1x2+2x3+3x4+...+2022x2023/2022x2023x2024
2xy-4x-y=3
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21 + 34 + 36 - 12
= (34 + 36) + (21 - 12)
= 70 + 9
= 79
Chúc bn học tốt!
\(B=\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{2022.2023}\)
\(B=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{2022}-\dfrac{1}{2023}\)
\(B=\dfrac{1}{2}-\dfrac{1}{2023}=\dfrac{2021}{4046}\)
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+....+\dfrac{1}{24\times25}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25}\)
\(=1-\dfrac{1}{25}\)
\(=\dfrac{24}{25}\)
\(\dfrac{1\times2+2\times3+3\times4+...+2022\times2023}{2022\times2023\times2024}=A\)
\(3A=\dfrac{1\times2\times3+2\times3\times3+3\times4\times3+...+2022\times2023\times3}{2022\times2023\times2024}\)
\(3A=\dfrac{1\times2\times\left(3-0\right)+2\times3\times\left(4-1\right)+3\times4\times\left(5-2\right)+...+2022\times2023\times\left(2024-2021\right)}{2022\times2023\times2024}\)
\(3A=\dfrac{1\times2\times3+2\times3\times4-2\times3\times1+...+2022\times2023\times2024-2022\times2023\times2021}{2022\times2023\times2024}\)
\(3A=\dfrac{2022\times2023\times2024}{2022\times2023\times2024}\)
\(3A=1\)
\(\Rightarrow A=1\div3\)
Vậy \(A=\dfrac{1}{3}\)
2xy - 4x - y = 3
2xy - 2x2 - y = 3
2x (y - 2) - y = 3
2x (y - 2) - (y - 2) = 3 + 2
(2x - 1) (y - 2) = 5
Ta có: 5 = 1 x 5 = (-1) x (-5)
Ta lập bảng:
Vậy (x; y) ϵ {(1; 7); (3; 3); (0; -3); (-2; 1)}