tìm y
5*y+3*y+2*y=20
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\(\dfrac{19}{20}-y=\dfrac{8}{5}-\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{19}{20}-y=\dfrac{32-15}{20}\)
\(\Leftrightarrow\dfrac{19}{20}-y=\dfrac{17}{20}\Leftrightarrow y=\dfrac{19}{20}-\dfrac{17}{20}=\dfrac{2}{20}=\dfrac{1}{10}\)
\(y:\dfrac{2}{3}=\dfrac{4}{9}.3\)
\(\Leftrightarrow y:\dfrac{2}{3}=\dfrac{12}{9}\Leftrightarrow y=\dfrac{12}{9}.\dfrac{2}{3}=\dfrac{8}{9}\)
\(a.\dfrac{19}{20}-y=\dfrac{17}{20}\)
\(y=\dfrac{2}{17}\)
\(b.y:\dfrac{2}{3}=\dfrac{4}{3}\)
\(y=\dfrac{8}{9}\)
Câu 3:
\(\dfrac{x}{y}=\dfrac{5}{9}\Rightarrow\dfrac{x}{5}=\dfrac{y}{9}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{5}=\dfrac{y}{9}=\dfrac{x-y}{5-9}=\dfrac{-40}{-4}=10\)
\(\dfrac{x}{5}=10\Rightarrow x=5\\ \dfrac{y}{9}=10\Rightarrow y=90\)
Câu b:
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{5x-2y}{10-6}=\dfrac{28}{4}=7\)
\(\dfrac{x}{2}=7\Rightarrow x=14\\ \dfrac{y}{3}=7\Rightarrow y=21\)
Câu c:
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{10}=\dfrac{x+y-1}{5+7-10}=\dfrac{20}{2}=10\)
\(\dfrac{x}{5}=10\Rightarrow x=50\\ \dfrac{y}{7}=10\Rightarrow y=70\\ \dfrac{z}{10}=10\Rightarrow z=100\)
Câu d:
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{z}{5}=\dfrac{3x-2y+2z}{9-8+10}=\dfrac{121}{11}=11\)
\(\dfrac{x}{3}=11\Rightarrow x=3\\ \dfrac{y}{4}=11\Rightarrow y=44\\ \dfrac{z}{5}=11\Rightarrow z=55\)
Câu e:
\(\dfrac{x}{4}=\dfrac{y}{2}\Rightarrow\dfrac{x}{8}=\dfrac{y}{6}\\\dfrac{y}{3}=\dfrac{z}{5}\Rightarrow\dfrac{y}{6}=\dfrac{z}{10}\\ \Rightarrow\dfrac{x}{8}=\dfrac{y}{6}=\dfrac{z}{10} \)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{8}=\dfrac{y}{6}=\dfrac{z}{10}=\dfrac{x+y-z}{8+6-10}=\dfrac{20}{4}=5\)
\(\dfrac{x}{8}=5\Rightarrow x=40\\ \dfrac{y}{6}=5\Rightarrow y=30\\ \dfrac{z}{10}=5\Rightarrow z=50\)
3) \(\Rightarrow\dfrac{x}{5}=\dfrac{y}{9}=\dfrac{x-y}{5-9}=\dfrac{-40}{-4}=10\)
\(\Rightarrow\left\{{}\begin{matrix}x=10.5=50\\y=10.9=90\end{matrix}\right.\)
4) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{5x}{10}=\dfrac{2y}{6}=\dfrac{5x-2y}{10-6}=\dfrac{28}{4}=7\)
\(\Rightarrow\left\{{}\begin{matrix}x=7.2=14\\y=7.3=21\end{matrix}\right.\)
5) \(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{10}=\dfrac{x+y-z}{5+7-10}=\dfrac{20}{2}=10\)
\(\Rightarrow\left\{{}\begin{matrix}x=10.5=50\\y=10.7=70\\z=10.10=100\end{matrix}\right.\)
6) \(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{z}{5}=\dfrac{3x}{9}=\dfrac{2y}{8}=\dfrac{2z}{10}=\dfrac{3x-2y+2z}{9-8+10}=\dfrac{121}{11}=11\)
\(\Rightarrow\left\{{}\begin{matrix}x=11.3=33\\y=11.4=44\\z=11.5=55\end{matrix}\right.\)
7) \(\Rightarrow\dfrac{x}{12}=\dfrac{y}{6}=\dfrac{z}{10}=\dfrac{x+y-z}{12+6-10}=\dfrac{20}{8}=\dfrac{5}{2}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{2}.12=30\\y=\dfrac{5}{2}.6=15\\z=\dfrac{5}{2}.10=25\end{matrix}\right.\)
Bài 5 :
a) \(\dfrac{y}{4}=\dfrac{9}{y}\)
\(\Rightarrow y^2=36\left(y\ne0\right)\)
\(\Rightarrow y=\pm6\)
b) \(\dfrac{y+7}{20}=\dfrac{5}{y+7}\left(y\ne-7\right)\)
\(\Rightarrow\left(y+7\right)^2=100=10^2\)
\(\Rightarrow\left[{}\begin{matrix}y+7=10\\y+7=-10\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}y=3\\y=-17\end{matrix}\right.\)
c) \(\dfrac{4-5y}{3}=\dfrac{y+2}{5}\)
\(\Rightarrow5\left(4-5y\right)=3\left(y+2\right)\)
\(\Rightarrow20-25y=3y+6\)
\(\Rightarrow28y=14\)
\(\Rightarrow y=\dfrac{14}{28}=\dfrac{1}{2}\)
Bài 4 :
\(\dfrac{a}{5}=\dfrac{b}{7}=\dfrac{c}{10}\)
\(\Rightarrow\dfrac{2a}{10}=\dfrac{3b}{21}=\dfrac{4c}{40}=\dfrac{2a+3b-4c}{10+21-40}=\dfrac{81}{-9}=-9\)
\(\Rightarrow\left\{{}\begin{matrix}a=-9.5=-45\\b=-9.7=-63\\c=-9.10=-90\end{matrix}\right.\)
a/\(\dfrac{19}{20}-y=\dfrac{8}{5}-\dfrac{3}{4}\)
\(\dfrac{19}{20}-y=\dfrac{17}{20}\)
\(y=\dfrac{19}{20}-\dfrac{17}{20}\)
\(y=\dfrac{2}{20}=\dfrac{1}{10}\)
b/\(y:\dfrac{2}{3}=\dfrac{4}{9}\times3\)
\(y:\dfrac{2}{3}=\dfrac{4}{3}\)
\(y=\dfrac{4}{3}\times\dfrac{2}{3}\)
\(y=\dfrac{8}{9}\)
#データネ
a) 19/20 - y = 8/5 - 3/4
19/20 - y = 17/20
y = 17/20 + 19/20
y = 36/20
b) y : 2/3 = 4/9 x 3
y : 2/3 = 12/9
y = 12/9 x 2/3
y = 24/27
tích cho mik nhaaaaaaaaaaa
Ta có \(\frac{x}{3}=\frac{y}{2};\frac{y}{3}=\frac{z}{5}\Leftrightarrow\frac{x}{9}=\frac{y}{6}=\frac{z}{10}\)
\(\Leftrightarrow\frac{x}{9}=\frac{y}{6}=\frac{z}{10}=\frac{x-y+z}{9-6+10}=\frac{20}{13}\)
Từ \(\frac{x}{9}=\frac{20}{13}\Rightarrow x=\frac{20.9}{13}=\frac{180}{13}\)
\(\frac{y}{6}=\frac{20}{13}\Rightarrow y=\frac{20.6}{13}=\frac{120}{13}\)
\(\frac{z}{10}=\frac{20}{13}\Rightarrow z=\frac{20.10}{13}=\frac{200}{13}\)
Giải:
Ta có: \(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{4}=\frac{y}{6}\)
\(\frac{y}{2}=\frac{z}{5}\Rightarrow\frac{y}{6}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{4}=\frac{y}{6}=\frac{z}{15}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{4}=\frac{y}{6}=\frac{z}{15}=\frac{x+y+z}{4+6+15}=\frac{-20}{25}=\frac{-4}{5}\)
+) \(\frac{x}{4}=\frac{-4}{5}\Rightarrow x=\frac{-16}{5}\)
+) \(\frac{y}{6}=\frac{-4}{5}\Rightarrow y=\frac{-24}{5}\)
+) \(\frac{z}{15}=\frac{-4}{5}\Rightarrow z=-12\)
Vậy bộ số \(\left(x,y,z\right)\) là \(\left(\frac{-16}{5},\frac{-24}{5},-12\right)\)
\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{28:7}{49:7}=\dfrac{4}{9}\\ Vậy:x=\dfrac{4.9}{4}=9\\ y=\dfrac{4.21}{9}=\dfrac{28}{3}\)
\(\dfrac{x}{2}=\dfrac{3}{y}\\ \Leftrightarrow x.y=2.3=6\\ Vậy:\left[{}\begin{matrix}\left(x;y\right)=\left(1;6\right)=\left(6;1\right)\\\left(x;y\right)=\left(2;3\right)=\left(3;2\right)\end{matrix}\right.\)
5.y+3.y+2.y=20
⇒y(5+3+2)=20
⇒y.10=20
⇒y=10-8 :))
y=2