Question

[Ánh Nguyễn]

   giúp em 3 bài này với ạ

Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 8:

a: \(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)

mà \(\dfrac{4}{5}>\dfrac{3}{5}\left(4>3\right)\)

nên \(\dfrac{8}{10}>\dfrac{3}{5}\)

b: \(\dfrac{12}{16}=\dfrac{12:4}{16:4}=\dfrac{3}{4}\)

\(\dfrac{28}{21}=\dfrac{28:7}{21:7}=\dfrac{4}{3}\)

mà \(\dfrac{3}{4}< 1;1< \dfrac{4}{3}\)

nên \(\dfrac{12}{16}< \dfrac{28}{21}\)

Bài 11:

a: \(\dfrac{9}{10}=1-\dfrac{1}{10}\)

\(\dfrac{10}{11}=1-\dfrac{1}{11}\)

10<11

=>\(\dfrac{1}{10}>\dfrac{1}{11}\)

=>\(-\dfrac{1}{10}< -\dfrac{1}{11}\)

=>\(-\dfrac{1}{10}+1< -\dfrac{1}{11}+1\)

=>\(\dfrac{9}{10}< \dfrac{10}{11}\)

b: \(\dfrac{125}{251}=1-\dfrac{126}{251}\)

\(\dfrac{127}{253}=1-\dfrac{126}{253}\)

251>253

=>\(\dfrac{126}{251}< \dfrac{126}{253}\)

=>\(-\dfrac{126}{251}>-\dfrac{126}{253}\)

=>\(-\dfrac{126}{251}+1>-\dfrac{126}{253}+1\)

=>\(\dfrac{125}{251}>\dfrac{127}{253}\)

Bài 10:

a: Vì 15>12>9

nên \(\dfrac{7}{15}< \dfrac{7}{12}< \dfrac{7}{9}\)

=>\(\dfrac{7}{15};\dfrac{7}{12};\dfrac{7}{9}\)

b: 3/5;5/7;1/7

\(\dfrac{3}{5}=\dfrac{3\cdot7}{5\cdot7}=\dfrac{21}{35};\dfrac{5}{7}=\dfrac{5\cdot5}{7\cdot5}=\dfrac{25}{35};\dfrac{1}{7}=\dfrac{1\cdot5}{5\cdot7}=\dfrac{5}{35}\)

mà 5<21<25

nên \(\dfrac{1}{7}< \dfrac{3}{5}< \dfrac{5}{7}\)

=>\(\dfrac{1}{7};\dfrac{3}{5};\dfrac{5}{7}\)

c: Vì 10>9>5>2

nên \(\dfrac{10}{11}>\dfrac{9}{11}>\dfrac{5}{11}>\dfrac{2}{11}\)

=>\(\dfrac{10}{11};\dfrac{9}{11};\dfrac{5}{11};\dfrac{2}{11}\)

Answer 2

[Akai Haruma]

Bài 8:

a. $\frac{8}{10}=\frac{8:2}{10:2}=\frac{4}{5}$

Vì $\frac{4}{5}> \frac{3}{5}$ nên $\frac{8}{10}> \frac{3}{5}$

b.

$\frac{12}{16}=\frac{12:4}{16:4}=\frac{3}{4}$

$\frac{28}{21}=\frac{28:7}{21:7}=\frac{4}{3}$

Vì $\frac{3}{4}< 1< \frac{4}{3}$

$\Rightarrow \frac{12}{16}< \frac{28}{21}$