\(6\frac{1}{7}\)x \(1\frac{6}{43}\)
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f: =>35x-5=96-6x
=>41x=101
hay x=101/41
g: =>3(x-3)=90-5(1-2x)
=>3x-9=90-5+10x
=>3x-9=10x+85
=>-7x=94
hay x=-94/7
h.3x - 2/6 - 5 = 3 - 2(x + 7)/4
<=> 3x - 2 - 30/6 = 3 - 2(x + 7)/4
<=> 3x - 32/6 = 3 - 2x - 14/4
<=> 3x - 32/6 = -2x - 11/4
<=> 6x - 64/12 = -6x - 33/12
<=> 6x - 64 = -6x - 33 <=> 12x = 31 <=> x = 31/12
a) \(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
=> \(\left(\frac{x-6}{7}+1\right)+\left(\frac{x-7}{8}+1\right)+\left(\frac{x-8}{9}+1\right)=\left(\frac{x-9}{10}+1\right)+\left(\frac{x-10}{11}+1\right)+\left(\frac{x-11}{12}+1\right)\)
=> \(\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}-\frac{x+1}{10}-\frac{x+1}{11}+\frac{x+1}{12}=0\)
=> \(\left(x+1\right)\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)=0\)
=> x + 1 = 0
=> x = -1
b) \(\frac{x-1}{2020}+\frac{x-2}{2019}-\frac{x-3}{2018}=\frac{x-4}{2017}\)
=> \(\left(\frac{x-1}{2020}-1\right)+\left(\frac{x-2}{2019}-1\right)-\left(\frac{x-3}{2018}-1\right)=\left(\frac{x-4}{2017}-1\right)\)
=> \(\frac{x-2021}{2020}+\frac{x-2021}{2019}-\frac{x-2021}{2018}=\frac{x-2021}{2017}\)
=> \(\left(x-2021\right)\left(\frac{1}{2020}+\frac{1}{2019}-\frac{1}{2018}-\frac{1}{2017}\right)=0\)
=> x - 2021 = 0
=> x = 2021
c) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
=> \(\frac{3}{4}x+3-\frac{2}{3}x+4-\frac{1}{6}x-1=\frac{1}{3}x+4-\frac{1}{3}x+3\)
=> \(-\frac{1}{12}x+6=7\)
=> \(-\frac{1}{12}x=1\)
=> x = -12
có liền luôn nè
1/2 -43/101+(-1/3)-1/6
= -43/101+(-1/3)-1/6+1/2
=-43/101+0
=-43/101
Cách 1 :
\(M=\left(7-\frac{1}{3}+\frac{3}{4}\right)-\left(6+\frac{2}{3}-\frac{1}{4}\right)\)
\(M=\left(\frac{84}{12}-\frac{4}{12}+\frac{9}{12}\right)-\left(\frac{72}{12}+\frac{8}{12}-\frac{3}{12}\right)\)
\(M=\frac{89}{12}-\frac{77}{12}\)
\(M=\frac{12}{12}\)
\(M=1\)
Cách 2 :
\(M=\left(7-\frac{1}{3}+\frac{3}{4}\right)-\left(6+\frac{2}{3}-\frac{1}{4}\right)\)
\(M=7-\frac{1}{3}+\frac{3}{4}-6-\frac{2}{3}+\frac{1}{4}\)
\(M=\left(7-6\right)-\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(M=1-1+1\)
\(M=1\)
Cách 1:
\(M=\left(7-\frac{1}{3}+\frac{3}{4}\right)-\left(6+\frac{2}{3}-\frac{1}{4}\right)\)
\(M=\frac{89}{12}-\frac{77}{12}\)
\(M=1\)
Cách 2:
\(M=\left(7-\frac{1}{3}+\frac{3}{4}\right)-\left(6+\frac{2}{3}-\frac{1}{4}\right)\)
\(M=7-\frac{1}{3}+\frac{3}{4}-6-\frac{2}{3}+\frac{1}{4}\)
\(M=\left(7-6\right)-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(M=1-1+1\)
\(M=1\)
a.x+30/100x=-1,1
13/10x=-1,1
x=-11/13
b. (x-1/2):1/3 +5/7=9/5/7
(x-1/2):1/3=9
x-1/2=3
x=7/2
c. -5/6-x=7/12-1/3
x=-5/6-7/12-1/3
x=-7/4
d. 3(x+3)=-15
x+3=-5
x=-8
e. (4,5-2x)(-11/7)=11/14
4,5-2x=11/14:-11/7
4,5-2x=-1/2
2x=4,5+1/2
2x=5
x=5/2
a) \(\frac{\left(5.2\right)}{3.2}-\frac{1}{2}x+\frac{1}{3}+\frac{1}{5}=\frac{\left(3.2\right)}{5}\)
\(\Leftrightarrow\)\(\frac{1}{2}-\frac{1}{2}x+\frac{8}{15}=\frac{6}{5}\)
\(\Leftrightarrow\)\(\frac{1}{2}-\frac{2}{3}=\frac{1}{2}x\)
\(\Leftrightarrow\)\(-\frac{1}{6}=\frac{1}{2}x\)
\(\Leftrightarrow\)x=-1/3
b) VT= \(\frac{\left(3.5.4.2\right)}{5.2.3}=4\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right):6+4=4:\frac{2}{3}=6\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right):6=2\)
\(\Leftrightarrow x-\frac{1}{2}=12\)
=> x= 12,5
\(6\frac{1}{7}x1\frac{6}{43}\)
= \(\frac{43}{7}x\frac{49}{43}\)
= \(\frac{49}{7}\)
= 7
43/7 * 49/43= 7