A) 2x+2 = 250 : 8
B) 5 * x + x = 150 : 2 + 3
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\(a,3\left(x+1\right)-2=4\)
\(\Leftrightarrow3\left(x+1\right)=6\)
\(\Leftrightarrow x+1=2\)
\(\Leftrightarrow x=1\)
Vậy x=1
Các câu còn lại lm tương tự nhé
\(3\left(x+1\right)-2=4\)
<=> \(3x+3-2=4\)
<=> \(3x=3\)
<=> \(x=1\)
\(5\left(x-2\right)+20=45\)
<=> \(5x-10=25\)
<=> \(x=7\)
\(700-7\left(x+2\right)=140\)
<=> \(7x+14=560\)
<=> \(7x=546\)
<=> \(x=78\)
\(200-5\left(2x+4\right)=100\)
<=> \(10x+20=100\)
<=> \(x=8\)
\(5\left(2x-4\right)+150=250\)
<=> \(10x-20=100\)
<=> \(x=12\)
học tốt
\(a,121-\left(115+x\right)=3x-\left(25-9-5x\right)-8\\ 121-115-x=3x-25+9+5x-8\\ 6-x=8x-24\\ 8x+x=-24-6\\ 9x=-30\\ x=-\dfrac{30}{9}=-\dfrac{10}{3}\\ ----\\ b,2^{x+2}.3^{x+1}.5^x=10800\\ \left(2.3.5\right)^x.2^2.3=10800\\ 30^x.12=10800\\ 30^x=\dfrac{10800}{12}=900=30^2\\ Vậy:x=2\)
a: 3x-7=8
=>3x=15
hay x=2
b: =>2x+5=3x-15
=>-x=-20
hay x=20
c: =>3(3x-4)=2(4x+1)
=>9x-12=8x+2
=>x=14
a) 3x-7=8
3x=15
x=3
Vậy..
b) 5+2x=3(x-5)
2x-3x=-5-15
-x=-20
x=20
Vậy...
c) 3x -4/2=4x+1/3
3x-4x=2+1/3
-x=7/3
x=-7/3
Vậy...
a, <=> x2 -2x +1 + 5x -x2 =8
<=> 3x +1 =8
<=> 3x = 7
<=> x= 7/3
b, thiếu đề
c, <=> 2x3 -1 + 2x(4 -x2) = 7
<=> 2x3 + 8x -23 = 8
<=> 8x =8
<=> x=1
a.
\(\left|5x\right|=3x+8\Leftrightarrow\left[{}\begin{matrix}-5x=3x+8\\5x=3x+8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)
b.
\(\left|-4x\right|=-2x+11\Leftrightarrow\left[{}\begin{matrix}-4x=-2x+11\\4x=-2x+11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=\dfrac{11}{6}\end{matrix}\right.\)
c.
\(\left|3x-1\right|=4x+1\Leftrightarrow\left[{}\begin{matrix}-3x+1=4x+1\\3x-1=4x+1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
d.
\(\left|3-2x\right|=3x-7\Leftrightarrow\left[{}\begin{matrix}-3+2x=3x-7\\3-2x=3x-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)
e.
\(9-\left|-5x\right|+2x=0\Leftrightarrow\left[{}\begin{matrix}9-5x+2x=0\\9+5x+2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{9}{7}\end{matrix}\right.\)
f.
\(\left(x+1\right)^2+\left|x+10\right|-x^2-12=0\Leftrightarrow\left[{}\begin{matrix}x^2+2x+1-x-10-x^2-12=0\\x^2+2x+1+x+10-x^2-12=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=21\\x=\dfrac{1}{3}\end{matrix}\right.\)
2:
a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8
=>x^2-x-12-x^2+4x+5=8
=>3x-7=8
=>3x=15
=>x=5
b: =>3x^2+3x-2x-2-3x^2-21x=13
=>-20x=15
=>x=-3/4
c: =>x^2-25-x^2-2x=9
=>-2x=25+9=34
=>x=-17
d: =>x^3-1-x^3+3x=1
=>3x-1=1
=>3x=2
=>x=2/3
b: \(5x^2+3x-2-4x^2+x+5=0\)
\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)
a) \(\Rightarrow x^8-2x^4-8=0\Rightarrow\left(x^4-4\right)\left(x^4+2\right)=0\)
\(\Rightarrow\left(x^2-2\right)\left(x^2+2\right)\left(x^4+2\right)=0\)
\(\Rightarrow x^2=2\Rightarrow x=\pm\sqrt{2}\)(do \(x^2+2\ge2>0,x^4+2\ge2>0\))
b) \(\Rightarrow x^2+4x+3=0\Rightarrow\left(x+1\right)\left(x+3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)
a) \(2^{x+2}=2^{50}:8\)
\(\Rightarrow2^{x+2}=2^{50}:2^3\)
\(\Rightarrow2^{x+3}=2^{47}\)
=> x + 3 = 47
=> x = 44
b) \(5.x+x=150:2+3\)
\(6x=78\)
=> x = 13