K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

8.50:

loading...

8.51:

loading...

Các tia trong hình vẽ là OA; Ox; OC; Oy; OB; CA; Ca; CB; Ca'; Aa; AC; AB; Aa'; BC,BA,Ba; Ba'

19 tháng 12 2019

I like living in the countryside because of some reasons. Environmentally speaking, it is a peaceful place. The air is fresh. The space is quiet. We can enjoy healthy natural conditions without worrying much about environmental pollution.

As for social security, the countryside is a safer place than a city. While urban security situation is always complicated with all kinds of crimes, rural areas are much more secure because most of countrymen are friendly and ready to help one another.

Moreover, rural life is also easier that in cities. People in cities are easy to get stressed because of pollution, job pressures, competitions, etc ... On the contrary, those bad things are very rare in the countryside. To sum up, except income matters, the countryside is a better residence than cities.

19 tháng 3 2022

mik cần gấp ai cứu đyy:((

 

 

 

 

 

ảnh bị lỗi kìa bạn

27 tháng 10 2021

okee mik sửa r

 

6 tháng 5 2023

4. a) PTHH: \(Zn+2HCl\rightarrow ZnCl_2+H_2\)

b) \(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)

Theo PTHH: \(n_{H_2}=n_{Zn}=0,1\left(mol\right)\)

\(\Rightarrow V_{H_2}=0,1.22,4=2,24\left(l\right)\)

c) \(C_M=\dfrac{n_{ct}}{V_{HCl}}=\dfrac{0,1}{0,8}=0,125M\)

d) \(H_2+CuO\rightarrow Cu+H_2O\)

\(n_{CuO}=\dfrac{0,8}{80}=0,1\left(mol\right)\)

Ta có: \(\dfrac{n_{H_2}}{1}=\dfrac{n_{CuO}}{1}\)

Vậy không có chất nào dư

\(\Rightarrow n_{Cu}=n_{H_2}=0,1\left(mol\right)\)

\(\Rightarrow m_{Cu}=0,1.64=6,4\left(g\right)\)

24 tháng 12 2020

a, \(B=\left(\frac{2x+1}{2x-1}+\frac{4}{1-4x^2}-\frac{2x-1}{2x+1}\right):\frac{x^2+2}{2x+1}\)

\(=\left(\frac{2x+1}{2x-1}+\frac{4}{\left(1-2x\right)\left(2x+1\right)}-\frac{2x-1}{2x+1}\right):\frac{x^2+2}{2x+1}\)

\(=\left(\frac{\left(2x+1\right)^2}{\left(2x-1\right)\left(2x+1\right)}-\frac{4}{\left(2x-1\right)\left(2x+1\right)}-\frac{\left(2x-1\right)^2}{\left(2x-1\right)\left(2x+1\right)}\right):\frac{x^2+2}{2x+1}\)

\(=\left(\frac{4x^2+4x+1-4-4x^2+4x-1}{\left(2x-1\right)\left(2x+1\right)}\right):\frac{x^2+2}{2x+1}\)

\(=\frac{8x-4}{\left(2x-1\right)\left(2x+1\right)}.\frac{2x+1}{x^2+2}=\frac{8x-4}{\left(2x-1\right)\left(x^2+2\right)}\)

b, Thay x = -1 ta được : \(\frac{9\left(-1\right)-4}{\left[2\left(-1\right)-1\right]\left[\left(-1\right)^2+2\right]}=-\frac{13}{-9}=\frac{13}{9}\)