264 -1 =
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`1+2+2^2+2^3+....+2^63`
`=2+2+2^2+2^3+....+2^63-1`
`=2.2+2^2+2^3+....+2^63-1`
`=2^2+2^2+2^3+....+2^63-1`
`=2.2^2+2^3+....+2^63-1`
`=2^3+2^3+...2^63-1`
`=2.2^3+....+2^63-1`
`=2^4+....+2^63-1`
`=2^{63}.2-1=2^64-1`
\(2^{2x+1}+4^{x+3}=264\)
\(=>2^{2x+1}+2^{2x+6}=264\)
\(=>2^{2x+1}.\left(1+2^5\right)=264\)
\(=>2^{2x+1}.\left(1+32\right)=264\)
\(=>2^{2x+1}.33=264\)
\(=>2^{2x+1}=264:33\)
\(=>2^{2x+1}=8\)
\(=>2^{2x+1}=2^3\)
\(=>2x+1=3\)
\(=>2x=3-1\)
\(=>2x=2\)
\(=>x=2:2\)
\(=>x=1\)
7,429 has 4 digits
it: 7, 4, 2, 9
264 has 3 digits
it: 2, 6, 4
\(2^{2x+1}+4^{x+3}=264\\ \Leftrightarrow2^{2x+1}+2^{2x+6}=264\\ \Leftrightarrow2^{2x+1}\left(1+2^5\right)=264\\ \Leftrightarrow2^{2x+1}\cdot33=264\\ \Leftrightarrow2^{2x+1}=8=2^3\\ \Leftrightarrow2x+1=3\Leftrightarrow x=1\)
\(=\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{2.\left(\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}\right)}.\dfrac{3.\left(\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}-\dfrac{1}{264}\right)}{\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}-\dfrac{1}{264}}\)
\(=\dfrac{1}{2}.3=\dfrac{3}{2}\)
Ta có: AB2=AM2+MB2
=22+12=5
Nên AB= √5
AC2=AN2+NC2
=9+16=52
nên AC=5
BC2=BK2+KC2
= 32+52=9+25=34
BC= √34
Giải:
Ta có: AB2=AM2+MB2
=22+12=5
Nên AB= √5
AC2=AN2+NC2
=9+16=52
nên AC=5
BC2=BK2+KC2
= 32+52=9+25=34
BC= √34
Lớp 4 chưa học lũy thừa em ơi!
1.8446744e+19